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bearhunter [10]
3 years ago
5

If the satellite weighs 1000g, orbits the Earth at an energy of 9.8 × 10 ^ 9j, what is the speed of the satellite?

Physics
1 answer:
Korvikt [17]3 years ago
3 0

Answer:

1.4×10⁵ m/s

Explanation:

Applying,

K = mv²/2............. Equation 1

Where K = Energy of the satellite, m = mass of the satellite, v = speed of the satellite.

make v the subject of the equation

v = √(2K/m)............ Equation 2

From the question,

Given: K = 9.8×10⁹ J, m = 1000 g = 1 kg

Substitute these values into equation 2

v = √(2×9.8×10⁹/1)

v = √(1.96×10¹⁰)

v = 1.4×10⁵ m/s

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You've been tired and lethargy what are two possible reasons?
dybincka [34]

Explanation:

physical exertion.

lack of physical activity.

lack of sleep.

being overweight or obese.

periods of emotional stress.

boredom.

grief.

taking certain medications, such as antidepressants or sedatives.

5 0
3 years ago
the distance between any two bodies is 10 M and the gravitational force between them is 3.2×10-⁹m. if the mass of one object is
cluponka [151]

Answer:

0.8 x 10^-9 kg

Explanation:

Given,

Distance ( R ) = 10 m

Force ( F ) = 3.2 x 10^-9 N

Mass ( m1 ) = 40 kg

To find : Mass ( m2 ) = ?

Formula : -

F = m1.m2 / R^2

m2 = FR^2 / m1

= 3.2 x 10^-9 x 10 / 40

= 3.2 x 10^-9 / 4

= ( 3.2 / 4 ) x 10^-9

m2 = 0.8 x 10^-9 kg

3 0
3 years ago
A solid cylinder has a diameter of 17.4 mm and a length of 50.3mm. It's mass is 49g . What is its density of the cylinder in met
Tamiku [17]

Answer:

4 tonne/m³

Explanation:

ρ = m / V

ρ = 49 g / (π (17.4 mm / 2)² (50.3 mm))

ρ = 0.0041 g/mm³

Converting to tonnes/m³:

ρ = 0.0041 g/mm³ (1 kg / 1000 g) (1 tonne / 1000 kg) (1000 mm / m)³

ρ = 4.1 tonne/m³

Rounding to one significant figure, the density is 4 tonne/m³.

6 0
3 years ago
A 210 kg meteoroid is heading toward the earth accelerates by 2.4 × 105 m/s2.
lidiya [134]
According to Newton's second law of motion, Force is the product of mass and acceleration of the object.
So, F = m * a

Here, m = 210 Kg
a = 2.4 * 10⁵ m/s²

Substitute their values, 
F = 210 * 2.4 * 10⁵ N
F = 504 * 10⁵ N
F = 5.04 * 10⁷ N

In short, Your Answer would be Option B

Hope this helps!
6 0
3 years ago
Given the height of rod,length of shadow of tree and length of shadow of the rod, estimate the height of the tree? Given:height
diamong [38]

Answer:

1000 cm.

Explanation:

To obtain the estimated tree height :

(Height of rod / length of rod shadow) = (height of tree / length of tree shadow)

Substituting values into the formula :

(150cm / 120 cm) = (height of tree / 800 cm)

Using cross multiplication :

Height of tree * 120 = 150 * 800

Height of tree = (150 * 800) / 120

Height of tree = 120,000 / 120

Height of tree = 1000

Hence, estimate height of tree = 1000 cm

5 0
3 years ago
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