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sweet [91]
3 years ago
8

Rutherford's gold foil experiment revealed that an atom's positive charge is concentrated in the atom's _____

Physics
1 answer:
Arte-miy333 [17]3 years ago
6 0
Atoms nucleus ! :-)
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Problem 5 A block of mass 3 kg slides on a horizontal, rough surface towards a spring with k = 500 N/m. The kinetic friction coe
vredina [299]

Answer:

Explanation:

given,

mass of block = 3 kg

spring constant k = 500 N/m

kinetic friction coefficient µk = 0.6

speed of block = 5 m/s

F = µk  N

F = 0.6 x 3 x 9.8

F = 17.64 N

using energy conservation

\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2+Fx

\dfrac{1}{2}\times 3 \times 5^2=\dfrac{1}{2}\times 500 \times x^2+17.64\times x

250 x² + 17.64 x - 37.5 = 0

on solving

x = 0.354 m

graph is attached below

4 0
4 years ago
Read 2 more answers
A beam oflight is reflected off a mirror. If the angle of incidence is 30 degrees, according to the Law of Reflection the angle
zaharov [31]

Answer:

30°

Explanation:

According to the second law of reflection, it States that the angle of incidence i is equal to the angle of reflection r.

The angle of incidence is known to be the angle between the incident ray and the normal.

The Angle of reflection is the angle between the reflected ray and the normal.

This normal ray is a ray that is perpendicular to the surface.

According to the question, if the beam of light is reflected off the surface and its angle of incidence is 30°, its angle of reflection will also be 30° i.e i=r = 30°

7 0
4 years ago
A spring that has a force constant of 1050 N/m is mounted vertically on the ground. A block of mass 1.95 kg is dropped from rest
aleksandrvk [35]

Answer:

25.2 cm

Explanation:

K = 1050 N/m

m = 1.95 kg

h = 1.75 m

By the conservation of energy, the potential energy of the block is converted into the potential energy stored in the spring

m g h = 1/2 x k x y^2

Where, y be the distance by which the spring is compressed.

1.95 x 9.8 x 1.75 = 1/2 x 1050 x y^2

33.44 = 525 x y^2

y = 0.252 m

y = 25.2 cm

8 0
3 years ago
A sample of oxygen gas at 25.0°c has its pressure tripled while its volume is halved. What is the final temperature of the gas?
Marat540 [252]

Answer:

447 K

Explanation:

25 C = 25 + 273 = 298 K

Assuming ideal gas, we can apply the ideal gas law

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

T_2 = T_1\frac{P_2}{P_1}\frac{V_2}{V_1}

Since pressure is tripled, then P_2 / P_1 = 3. Volume is halved, then V_2 / V_1 = 0.5

T_2 = 298*3*0.5 = 447 K

4 0
3 years ago
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How much force is needed to make a 225 kg object accelerate at a rate of 2.5 m/s²?
aksik [14]

F=ma using formula and solve your question

8 0
3 years ago
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