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Elina [12.6K]
3 years ago
13

Given the height of rod,length of shadow of tree and length of shadow of the rod, estimate the height of the tree? Given:height

of rod=150cm,Length of shadow of the rod=120cm and length of shadow of the tree =800cm​
Physics
1 answer:
diamong [38]3 years ago
5 0

Answer:

1000 cm.

Explanation:

To obtain the estimated tree height :

(Height of rod / length of rod shadow) = (height of tree / length of tree shadow)

Substituting values into the formula :

(150cm / 120 cm) = (height of tree / 800 cm)

Using cross multiplication :

Height of tree * 120 = 150 * 800

Height of tree = (150 * 800) / 120

Height of tree = 120,000 / 120

Height of tree = 1000

Hence, estimate height of tree = 1000 cm

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Which type of force will an object move towards?
Makovka662 [10]

Answer:

i think it's weakest

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Explanation:

if a strong force is acting on something it will push it away, meaning the object would go towards the weaker force

4 0
3 years ago
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Choose the situation below in which the force applied is the greatest.
Gnesinka [82]

Answer:

D

Explanation:

We know the formula for Work to be:

W = f * d

Where W is work done

f is force

d is the distance

A)

Work = 50

Distance = 50

So, Force is:

Force = 50/50 = 1

B)

Work = 400

Distance = 80

Force = 400/80 = 5

C)

Work = 365

Distance = 73

Force = 365/73 = 5

D)

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Distance = 16

Force = 144/16 = 9

Hence, D is the situation in which the force applied is the greatest.

6 0
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Which of the following is a fundamental quantity?
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-- Volume . . . made out of 3 dimensions of length

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-- Area . . . made out of 2 dimensions of length

-- Acceleration . . . made out of length and time

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7 0
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The rope of a swing is 3.10 m long. Calculate the angle from the vertical at which a 76.0 kg man must begin to swing in order to
kakasveta [241]

Answer:

The angle from the vertical is 48.72°

Explanation:

Given :

Length of rope l = 3.10 m

Mass of man m = 76 Kg

Mass of car M = 1520 Kg

Velocity of car v = 1.01 \frac{m}{s}

According to conservation law,

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   \frac{1}{2} M v^{2} = mgh

We calculate height,

   h = \frac{M v^{2} }{2mg}

   h = \frac{1520(1.01)^{2} }{2\times 75 \times 9.8}                      ( ∵ g = 9.8 \frac{m}{s^{2} } )

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This is the distance of the rope at the bottom,

So we take difference of it.

⇒ 3.10 - 1.05 = 2.05

We can calculate angle between them,

\cos \theta = \frac{2.05}{3.10}  = 0.6597

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Therefore, the angle from the vertical is 48.72°

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