Answer:
The percentage of the weight supported by the front wheel is A= 19.82 %
Explanation:
B] Let the mass of plane be m, force on backwheels be Nb and nosewheel be Nn
Torque equation about nose wheel,
mg*(2.58-0.8) - Nb *(3.02-0.8) = 0
Nb = mg*(2.58-0.8)/(3.02-0.8) = 0.8018 mg
Nn = mg - Nb = (1-0.8018) mg = 0.1982mg
Weight percentage supported by front wheel = 19.82% answer
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A pair of equal gravitational forces ... one in each direction ...
exists between every speck of mass in the universe and every
other speck of mass.