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Elina [12.6K]
3 years ago
13

Given the height of rod,length of shadow of tree and length of shadow of the rod, estimate the height of the tree? Given:height

of rod=150cm,Length of shadow of the rod=120cm and length of shadow of the tree =800cm​
Physics
1 answer:
diamong [38]3 years ago
5 0

Answer:

1000 cm.

Explanation:

To obtain the estimated tree height :

(Height of rod / length of rod shadow) = (height of tree / length of tree shadow)

Substituting values into the formula :

(150cm / 120 cm) = (height of tree / 800 cm)

Using cross multiplication :

Height of tree * 120 = 150 * 800

Height of tree = (150 * 800) / 120

Height of tree = 120,000 / 120

Height of tree = 1000

Hence, estimate height of tree = 1000 cm

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Answer:

altruism

Explanation:

4 0
3 years ago
An airplane is fl ying with a velocity of 240 m/s at an angle of 30.0° with the horizontal, as the drawing shows. When the altit
netineya [11]

Answer:

\theta=41.52^{\circ}

Explanation:

Given that,

Velocity of the  airplane, v = 240 m/s

Angle with horizontal, \theta=30^{\circ}

The altitude of the plane is 2.4 km, d = 2400 m

Vertical speed of the airplane, v_y=v\ sin\theta=240\ sin(30)=120\ m/s

Horizontal speed of the airplane, v_x=v\ cos\theta=240\ sin(30)=207.84\ m/s

So, the equation of the projectile for the flare is given by :

4.9t^2+120t-2400=0

On solving the above equation, we get the value of t as:

t = 13.04 seconds

Horizontal distance travelled,

d=v_x\times t

d=207.84\times 13.04

d = 2710.23 m

Let \theta is the angle with which it hits the target. So,

tan\theta=\dfrac{2400}{2710.23}

\theta=41.52^{\circ}

Hence, this is the required solution.

4 0
3 years ago
Richard's doctor says that he has become obese. What health risks is Richard now facing?
Minchanka [31]

Answer:

The answer would be A.)Early signs of cardiovascular disease and sleep apnea.

Explanation:

I got it right on the hope test.

4 0
3 years ago
A screen is separated from a double-slit source by a distance L. When light of wavelength 563 nm is incident on the double slit,
Andrew [12]

Answer:

β 2 = 0.02575 mm

Explanation:

given data

wavelength = 563 nm

separation distance between adjacent bright fringes =  0.0290 mm

wavelength = 500 nm

solution

we get here separation distance between adjacent bright fringes that is express as

β = \frac{\lambda D }{d}    ..................................1

here D is distance from plane of slit to screen

and d is slit sepation that is constant

so

\frac{\beta 1}{\beta 2} = \frac{\lambda 1}{\lambda 2}  

β 2 = \frac{500}{563} \times 0.0290  

β 2 = 0.02575 mm

7 0
3 years ago
Masses M1 and M2 are initially separated by a distance Ra. Mass M2 is now moved further away from mass M1 such that their final
Komok [63]

Answer:

A. Wab > 0.

Explanation:

Work done will be equal to change in gravitational energy in the whole process .

When Masses M₁ and M₂ are initially separated by a distance Ra

their gravitational energy

= - G M₁ M₂ / Ra

When mass M₂ is now moved further away from mass M₁ such that their final separation is Rb

their gravitational energy

= - G M₁ M₂ / Rb

Change in gravitational energy

= - G M₁ M₂ / Rb - (  - G M₁ M₂ / Ra )

=  G M₁ M₂ / Ra -  - G M₁ M₂ / Rb

=   G M₁ M₂ ( 1 / Ra - Rb )

As Ra < Rb

1/Ra > 1 / Rb

So change in gravitational energy is positive

So

Wab > 0.

3 0
3 years ago
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