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son4ous [18]
3 years ago
13

Question 3

Physics
1 answer:
wariber [46]3 years ago
7 0

Answer:

1200J

21.8Watts

Explanation:

Given parameters:

Force  = 400N

Distance  = 3m

Time  = 55s

Unknown:

Work done  = ?

Power  = ?

Solution:

Work done is the force applied to move a body through a certain distance.

Power is the rate at which work is done

 Work done  = Force x distance  = 400 x 3 = 1200J

Power  = \frac{work done }{time}   = \frac{1200}{55}    = 21.8Watts

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wlad13 [49]

<u>Question</u> :-

  • Two spheres of mass 2 kg and 3 kg respectively are situated so that the gravitational force between them is \bf 2.5 \times 10^{-8 }NCalculate the distance between them.

<u>We are given </u>:-

  • Mass of first sphere, m = 2 kg
  • Mass of second sphere, M= 3 kg
  • Gravitational force ,F = \bf 2.5 \times  10^{-8} N
  • G = 6.67×10⁻¹¹ Nm²/kg²

We are asked to find distance between them.

  • We know that according to gravitational law, we have force of attraction between two bodies is directly proportional to the product of masses of bodies and inversely proportional to the square of distance between them.Which is given by –

\qquad \pink{\twoheadrightarrow\sf F = \dfrac{GmM}{r^2}}

<u>Substituting values, we get</u> –

\qquad \twoheadrightarrow\sf  2.5\times 10^{-8} = \dfrac{6.67\times10^{-11}\times2\times3}{r^2}

\qquad \twoheadrightarrow\sf  2.5\times 10^{-8} = \dfrac{4.002\times10^{-8}}{r^2}

\qquad \twoheadrightarrow\sf  \dfrac {r^2}{4.002\times10^{-10}}=\dfrac{1}{2.5\times10^{-8}}

\qquad \twoheadrightarrow\sf   r^2 = \dfrac{4.002\times10^{-10}}{2.5\times10^{-8}}

\qquad \twoheadrightarrow\sf   r^2 = 1.6 \times 10^{-10}\times 10^{8}

\qquad \twoheadrightarrow\sf   r^2 = 1.6 \times 10^{-10+8}

\qquad \twoheadrightarrow\sf   r^2= 1.6\times10^{-2}

\qquad \twoheadrightarrow\sf   r=\sqrt{1.6\times10^{-2}}

\qquad \twoheadrightarrow\sf   r=1.265\times10^{-1} \: m

\qquad \pink{\twoheadrightarrow\bf  r = 12.65 \:cm}

  • Henceforth,distance between them will be 12.65 cm.
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Yuliya22 [10]

Answer:

The value is q = 3.4 *10^{-6} \ C

Explanation:

From the question we are told that

    The mass of each sphere is m_1 = m_2  = m  =  0.020 \ kg

     The length of the string is  l = 0.18 \  m

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Generally the force acting between the forces is mathematically represented as

       F  =  T cos \theta =  \frac{k*  q^2}{ r^2}

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Generally from Pythagoras theorem the radius of the circular curve created by the force is

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=>      q = tan(7)* \frac{ 0.02 * 9.8 * 0.043^2 }{9*10^{9}}

=>      q = 3.4 *10^{-6} \ C

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