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3 years ago

13

Question 3

1 answer:

wariber [46]3 years ago

7 0

Answer:

1200J

21.8Watts

Explanation:

Given parameters:

Force = 400N

Distance = 3m

Time = 55s

Unknown:

Work done = ?

Power = ?

Solution:

Work done is the force applied to move a body through a certain distance.

Power is the rate at which work is done

Work done = Force x distance = 400 x 3 = 1200J

Power = $\frac{work done }{time}$ = $\frac{1200}{55}$ = 21.8Watts

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4 years ago

8. Two spheres of mass 2 kg and 3 kg respectively are situated so that the gravi- tational force between them is 2,5 x 10-8 N. C

wlad13 [49]

<u>Question</u> :-

Two spheres of mass 2 kg and 3 kg respectively are situated so that the gravitational force between them is $\bf 2.5 \times 10^{-8 }N$ Calculate the distance between them.

<u>We are given </u>:-

Mass of first sphere, m = 2 kg
Mass of second sphere, M= 3 kg
Gravitational force ,F = $\bf 2.5 \times 10^{-8} N$
G = 6.67×10⁻¹¹ Nm²/kg²

We are asked to find distance between them.

We know that according to gravitational law, we have force of attraction between two bodies is directly proportional to the product of masses of bodies and inversely proportional to the square of distance between them.Which is given by –

$\qquad$ $\pink{\twoheadrightarrow\sf F = \dfrac{GmM}{r^2}}$

<u>Substituting values, we get</u> –

$\qquad$ $\twoheadrightarrow\sf 2.5\times 10^{-8} = \dfrac{6.67\times10^{-11}\times2\times3}{r^2}$

$\qquad$ $\twoheadrightarrow\sf 2.5\times 10^{-8} = \dfrac{4.002\times10^{-8}}{r^2}$

$\qquad$ $\twoheadrightarrow\sf \dfrac {r^2}{4.002\times10^{-10}}=\dfrac{1}{2.5\times10^{-8}}$

$\qquad$ $\twoheadrightarrow\sf r^2 = \dfrac{4.002\times10^{-10}}{2.5\times10^{-8}}$

$\qquad$ $\twoheadrightarrow\sf r^2 = 1.6 \times 10^{-10}\times 10^{8}$

$\qquad$ $\twoheadrightarrow\sf r^2 = 1.6 \times 10^{-10+8}$

$\qquad$ $\twoheadrightarrow\sf r^2= 1.6\times10^{-2}$

$\qquad$ $\twoheadrightarrow\sf r=\sqrt{1.6\times10^{-2}}$

$\qquad$ $\twoheadrightarrow\sf r=1.265\times10^{-1} \: m$

$\qquad$ $\pink{\twoheadrightarrow\bf r = 12.65 \:cm}$

Henceforth,distance between them will be 12.65 cm.

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2 years ago

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icang [17]

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2 years ago

Two identical small charged spheres hang in equilibrium with equal masses (0.02kg). The length of the strings is equal (0.18m) a

Yuliya22 [10]

Answer:

The value is $q = 3.4 *10^{-6} \ C$

Explanation:

From the question we are told that

The mass of each sphere is $m_1 = m_2 = m = 0.020 \ kg$

The length of the string is $l = 0.18 \ m$

The angle of with the vertical is $\theta = 7^o$

The acceleration due to gravity is $g = 9.8 \ m/s^2$

Generally the force acting between the forces is mathematically represented as

$F = T cos \theta = \frac{k* q^2}{ r^2}$

=> $T cos \theta = \frac{k* q^2}{ r^2}$

Generally from Pythagoras theorem the radius of the circular curve created by the force is

$r = 2 L sin (\theta )$

=> $r = 2* 0.180 sin (7)$

=> $r = 0.043 \ m$

=> $q = tan \theta * \frac{m * g * r^2 }{k}$

=> $q = tan(7)* \frac{ 0.02 * 9.8 * 0.043^2 }{9*10^{9}}$

=> $q = 3.4 *10^{-6} \ C$

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3 years ago

Circular motion formulas

KIM [24]

Answer:

I found this don't know if its any use or not

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3 years ago