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Svetlanka [38]
3 years ago
11

A sample of gas at 15 atmospheres and 445 K is cooled to 250 K. What pressure will the gas be under after it is cooled? Round to

the nearest hundredth.
A. 26.7 atm
B. 25 atm
C. 8.43 atm
D. 10 atm
Chemistry
1 answer:
faltersainse [42]3 years ago
7 0

Answer:

Explanation: 8.43

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Answer: 3.024 g grams of hydrogen are needed to  convert 76 grams of chromium(III) oxide, Cr_{2}O_{3}

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The reaction equation for given reaction is as follows.

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Here, 1 mole of Cr_{2}O_{3} reacts with 3 moles of H_{2}.

As mass of chromium (III) oxide is given as 76 g and molar mass of chromium (III) oxide (Cr_{2}O_{3}) is 152 g/mol.

Number of moles is the mass of substance divided by its molar mass. So, moles of Cr_{2}O_{3} is calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{76 g}{152 g/mol}\\= 0.5 mol

Now, moles of H_{2}.given by 0.5 mol of Cr_{2}O_{3} is calculated as follows.

0.5 mol Cr_{2}O_{3} \times \frac{3 mol H_{2}}{1 mol Cr_{2}O_{3}}\\= 1.5 mol H_{2}

As molar mass of H_{2} is 2.016 g/mol. Therefore, mass of H_{2} is calculated as follows.

No. of moles = \frac{mass}{molar mass}\\1.5 mol = \frac{mass}{2.016 g/mol}\\mass = 3.024 g

Thus, we can conclude that 3.024 g grams of hydrogen are needed to  convert 76 grams of chromium(III) oxide, Cr_{2}O_{3}.

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