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natita [175]
3 years ago
8

31. Use the equation given below to answer the following question: If 755 kJ of heat was absorbed, what mass of carbon dioxide r

eacted?
2CO2 + 43.9 kJ → 2CO +O2
Chemistry
1 answer:
brilliants [131]3 years ago
8 0

Answer:

1514g of CO₂ reacted

Explanation:

Based on the reaction:

2CO₂ + 43.9kJ → 2CO + O₂

<em>2 moles of carbon dioxide require 43.9kJ of energy to produce 2 moles of carbon monoxide and 1 mole of oxygen</em>

<em />

To solve this question, we must convert the 755kJ of energy to moles of carbon dioxide that reacts and to find the mass as follows:

755kJ * (2 moles CO₂ / 43.9kJ)  =34.4 moles of CO₂ are produced

<em>Mass CO₂: Molar mass: 44.01g/mol</em>

34.4 moles CO₂ * (44.01g / mol) =

<h3>1514g of CO₂ reacted</h3>
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Part A
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These are two questions and two answers

Question 1.

Answer:

  • <u>7.33 × 10 ⁻³ c</u>

Explanation:

<u>1) Data:</u>

a) m = 9.11 × 10⁻³¹ kg

b) λ =  3.31 × 10⁻¹⁰ m

c) c = 3.00 10⁸ m/s

d) s = ?

<u>2) Formula:</u>

The wavelength (λ), the speed (s), and the mass (m) of the particles are reltated by the Einstein-Planck's equation:

  • λ = h / (m.s)

  • h is Planck's constant: h= 6.626×10⁻³⁴J.s

<u>3) Solution:</u>

Solve for s:

  • s = h / (m.λ)

Substitute:

  • s = 6.626×10⁻³⁴J.s / ( 9.11 × 10⁻³¹ kg ×  3.31 × 10⁻¹⁰ m) = 2.20 × 10 ⁶ m/s

To express the speed relative to the speed of light, divide by c =  3.00 10⁸ m/s

  • s =  2.20 × 10 ⁶ m/s / 3.00 10⁸ m/s = 7.33 × 10 ⁻³

Answer: s = 7.33 × 10 ⁻³ c

Question 2.

Answer:

  • 2.06 × 10 ⁻³⁴ m.

Explanation:

<u>1) Data:</u>

a) m = 45.9 g (0.0459 kg)

b) s = 70.0 m/s

b) λ =  ?

<u>2) Formula:</u>

Macroscopic matter follows the same Einstein-Planck's equation, but the wavelength is so small that cannot be detected:

  • λ = h / (m.s)

  • h is Planck's constant: h= 6.626×10⁻³⁴J.s

<u>3) Solution:</u>

  • λ = h / (m.s)

Substitute:

  • λ =  6.626×10⁻³⁴J.s / ( 0.0459 kg ×  70.0 m/s) = 2.06 × 10 ⁻³⁴ m

As you see, that is tiny number and explains why the wave nature of the golf ball is undetectable.

Answer: 2.06 × 10 ⁻³⁴ m.  

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