Answer:
4.07
Explanation:
There is some info missing. I think this is the original question.
<em>A solution is prepared at 25 °C that is initially 0.057 M in nitrous acid (HNO₂), a weak acid with Ka = 4.5 × 10⁻⁴, and 0.30 M in sodium nitrite (NaNO₂). Calculate the pH of the solution. Round your answer to 2 decimal places.</em>
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Nitrous acid is a weak acid and nitrite (coming from sodium nitrite) is its conjugate base. Together, the form a buffer system. We can calculate its pH using the Henderson-Hasselbach equation.
pH = pKa + log [base]/[acid]
pH = -log 4.5 × 10⁻⁴ + log 0.30/0.057
pH = 4.07
When comparing single bonds between atoms of comparable types, the stronger the bond is, the bigger the atom, the weaker it is.
The length of the X-H bond lengthens while the strength of the bond shortens with increasing halogen size (F-H strongest, I-H weakest). When comparing single bonds between atoms of similar sorts, the larger the atom, the weaker the bond. It can be explained by the fact that less energy is required to break the bond the bigger the atom's atomic size. The force of attraction from the nucleus to the outermost orbit will be less for iodine since it has a larger atom than the other elements in the group.
Learn more about single bonds here-
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In order to find out how many protons a sodium atom has, you have to look at the periodic table. Sodium is Na on the periodic table and you look for the number on the top of the symbol and you can see that it has 11 protons. To find out how many neutrons, you have to subtract 11 from the mass number, which is 23. 23-11 = 12.
12 neutrons; 11 protons
Answer:
The transiontions metal group
Explanation:
