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natita [175]
3 years ago
8

31. Use the equation given below to answer the following question: If 755 kJ of heat was absorbed, what mass of carbon dioxide r

eacted?
2CO2 + 43.9 kJ → 2CO +O2
Chemistry
1 answer:
brilliants [131]3 years ago
8 0

Answer:

1514g of CO₂ reacted

Explanation:

Based on the reaction:

2CO₂ + 43.9kJ → 2CO + O₂

<em>2 moles of carbon dioxide require 43.9kJ of energy to produce 2 moles of carbon monoxide and 1 mole of oxygen</em>

<em />

To solve this question, we must convert the 755kJ of energy to moles of carbon dioxide that reacts and to find the mass as follows:

755kJ * (2 moles CO₂ / 43.9kJ)  =34.4 moles of CO₂ are produced

<em>Mass CO₂: Molar mass: 44.01g/mol</em>

34.4 moles CO₂ * (44.01g / mol) =

<h3>1514g of CO₂ reacted</h3>
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Copper is formed when aluminum reacts with copper (II) sulfate in a single-replacement reaction. How many moles of copper can be
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Answer:

The answer to your question is the limiting reactant is CuSO₄ and 0.975 moles of Cu were obtained

Explanation:

moles of Copper = ?

mass of Aluminum = 29 g

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Limiting reactant = ?

Balanced Chemical reaction

                  3 CuSO₄   +  2 Al   ⇒   3 Cu   +  Al₂(SO₄)₃

Calculate the moles of reactants

CuSO₄ = 64 + 32 + (16 x 4) = 160g

Al = 27 g

                160 g of CuSO₄  ----------------- 1 mol

                156 g                   -----------------  x

                      x = (156 x 1) / 160

                      x = 0.975 moles

               27 g of Al -------------------------- 1 mol

               29 g of Al -------------------------- x

                x = (29 x 1)/27

                x = 1.07 moles

Calculate proportions to find the limiting reactant

Theoretical     3 moles CuSO₄/2 moles Al = 1.5 moles

Experimental  0.975 moles CuSO₄/1.07 moles = 0.91

The experimental proportion was lower than the theoretical proportion that means that the limiting reactant is CuSO₄.      

                    3 moles of CuSO₄ ------------------ 3 moles of Cu

                 0.975 moles of CuSO₄ ---------------  x

                         x = (0.975 x 3)/3

                        x = 0.975 moles of Cu were obtained.        

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Answer:

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Answer:

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