The specific heat capacity the substance is calculated using the below formula
Q(heat) = Mc delta T
Q =1560 cal
m(mass) 312 g
delta T (change in temperature ) = 15 c
C= specific heat capacity=?
by making c the subject of the formula
c=Q/m delta T
= 1560 cal/ 312g x 15 c = 0.33 cal/g/c (answer B)
1.8 L
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Explanation</h3>
The volume of a gas, V, is inversely proportional to the pressure on it, P. That is:
V₁ · T₁ = V₂ · T₂.
Rearranging gives:
V₂ = V₁ · T₁ / T₂ = 4.2 × (101 / 235) = 1.8 L
Answer:
the complete question is found in the attachment
Explanation:
the complete explanation is found in the attachment
First, we'll identify the beaker containing pure water as follows:
We'll take equal masses from each of the three beakers and measure the mass of each.
We'll then identify the density of each by using the rule : density =mass/volume
Pure water will be the liquid having density equal to 1 gm/cm^3
Then, we'll differentiate between the salt and sugar solution by measuring the conductivity of each solution. Salt solution is a good conductor while solution of sugar is a bad conductor.
