Assume that adults have IQ scores that are normally distributed with a mean of μ= 105 and a standard deviation Ï =20 . Find the
probability that a randomly selected adult has an IQ between 85 and 125 .
1 answer:
Answer:
0.68268
Step-by-step explanation:
We solve using z score
z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
For x = 85
z = 85 - 105/20
z = -1
Probability value from Z-Table:
P(x = 85) = 0.15866
For x = 125
z = 125 - 105/20
z = 1
Probabilty value from Z-Table:
P(x = 125) = 0.84134
The probability that a randomly selected adult has an IQ between 85 and 125 is calculated as:
P(x = 125) - P(x = 85)
= 0.84134 - 0.15866
= 0.68268
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