Solution:
Area of Quadrilateral ACDO= Area (ΔAOD)+Area(ΔACD)-----(1)
Area of Quadrilateral ABDO= Area (ΔAOD)+Area(ΔABD)------(2)
⇒ (1) = 5 ×(2)→→→→GIven
→Area (ΔAOD)+Area(ΔACD)=5 Area (ΔAOD)+5 Area(ΔABD),
→5 Area (ΔABD)+4 Area (ΔAOD)-Area (ΔACD)=0-----(3)
As, Area of a Triangle
Area (ΔACD)
Area (ΔABD)
Area (ΔAOD)
Putting these values in equation (3)
→20+24-12+2 y=0
→ 2 y= -32
Dividing both sides by , 2 we get
→y= -16
Answer:
54 square meters
Step-by-step explanation:
Similar figures have corresponding lengths as equal ratios.
Smaller trapezoid's base is given 12 and larger trapezoids base is given 18, so the scale factor is
<em>this means the lengths of larger is 1.5 times lengths of smaller.</em>
<em />
In terms of area, the scale factor is squared. Hence the scale factor for area is
<em>this means the area of larger is 2.25 times the area of smaller.</em>
<em />
Now, Let area of smaller trapezoid be x so we can say:
<em>to nearest square meter, </em><em>x = 54 meters squared</em>