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cestrela7 [59]
2 years ago
12

Calculate ∆U (the change in internal energy) for a system on which 850.00

Chemistry
1 answer:
Illusion [34]2 years ago
6 0

Answer:

The heat gain by the system,

q

=

−

250

kJ

.

The work done on the system ,

w

=

−

500

kJ

.

The First Law of Thermodynamics state that

Δ

U

=

q

+

w

=

−

750

kJ

Explanation:

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High-pressure liquid chromatography (HPLC) is a method used in chemistry and biochemistry to
Alchen [17]

Answer:

2,400,000 torr (3 s.f.)

Explanation:

Convert the pressure from Pascal to atm first:

\boxed{1 \: atm = 101325 \:Pa }

3.20 ×10⁸ Pa

= [(3.20 ×10⁸) ÷101325] atm

= 3158.2 atm (5 s.f.)

Convert atm to torr:

\boxed{1 \: atm = 760 \: torr}

3158.2 atm

= (3158.2 ×760) torr

= 2400000 torr (3 s.f.)

6 0
2 years ago
Whats the unit for mass
sesenic [268]

Answer:

The unit for mass is the kilogram (Kg).

Explanation:

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5 0
3 years ago
Read 2 more answers
15. Which sample of argon gas has the same number of atoms as a 100.-milliliter sample of helium gas at 1.0 atm and 300. K? A) 5
OLga [1]

The sample of argon gas that has the same number of atoms as a 100 milliliter sample of helium gas at 1.0 atm and 300 is 100. mL at 1.0 atm and 300. K

The correct option is D.

<h3>What is the number of moles of gases in the given samples?</h3>

The number of moles of gases in each of the given samples of gas is found below using the ideal gas equation.

The ideal gas equation is: PV/RT = n

where;

  • P is pressure
  • V is volume
  • n is number of moles of gas
  • T is temperature of gas
  • R is molar gas constant = 0.082 atm.L/mol/K

Moles of gas in the given helium gas sample:

P = 1.0 atm, V = 100 mL or 0.1 L, T = 300 K

n =  1 * 0.1 / 0.082 * 300

n = 0.00406 moles

For the argon gas sample:

A. n =  1 * 0.05 / 0.082 * 300

n = 0.00203 moles

B. n =  0.5 * 0.05 / 0.082 * 300

n = 0.00102 moles

C. n =  0.5 * 0.1 / 0.082 * 300

n = 0.00203 moles

D. n =  1 * 0.1 / 0.082 * 300

n = 0.00406 moles

Learn more about ideal gas equation at: brainly.com/question/24236411

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8 0
1 year ago
A compound of a transition metal and iodine is 56.7% metal by mass.How many grams of the metal can be obtained from 630 g of thi
erma4kov [3.2K]

Answer:

357 g of the transition metal are present in 630 grams of the compound of the transition metal and iodine

Explanation:

In any sample of the compound, the percentage by mass of the transition metal is 56.7%. This means that for a 100 g sample of the compound, 56.7 g is the metal while the remaining mass, 43.3 g is iodine.

Given mass of sample compound = 630 g

Calculating the mass of iodine present involves multiplying the percentage by mass composition of the metal by the mass of the given sample;

56.7 % = 56.7/100 = 0.567

Mass of transition metal = 0.567 * 630 = 357.21 g

Therefore, the mass of the transition metal  present in 630 g of the compound is approximately 357 g

4 0
3 years ago
If a drop of blood is 0.05 mL, how many drops of blood are in the blood collection tube that holds 2 mL?
Irina18 [472]
40 drops of blood in a tube that holds 2 mL
5 0
3 years ago
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