Because it is a mix of H2O (water) and NaCl (salt)
We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.
First, we need to determine the required moles of CaCl₂. We have 500 mL (0.500 L) of a 0.360 M solution (0.360 moles of CaCl₂ per liter of solution).

Then, we will convert 0.180 moles to grams using the molar mass of CaCl₂ (110.98 g/mol).

To prepare the solution, we weigh 20.0 g of CaCl₂ and add it to a beaker with enough distilled water to dissolve it. We stir it, heat it if necessary, and when we have a solution, we transfer it to a 500 mL flask and complete it to the mark with distilled water.
We need to measure 20.0 grams of CaCl₂ to prepare 500 mL of 0.360 M solution.
You can learn more about solutions here: brainly.com/question/2412491
Answer:
52.5 mol O2
Explanation:
4 FeCl3 + 6 O2 -> 2 Fe2O3 +6 Cl2
4 mol FeCl3 -> 6 mol O2
35.0 mol FeCl3 -> x
x= (35.0 mol FeCl3 * 6 mol O2)/4 mol FeCl3
x=52.5 mol O2
The answer is by "splitting water".
hope this helps