Answer:
3,85 g of Fe
Explanation:
1- The first thing to do is calculate the molar mass of the Fe2O3 compound. With the help of a periodic table, the weights of the atoms are searched, and the sum is made:
Molar mass of Fe2O3 = (2 x mass of Fe) + (3 x mass of O) = 2 x 55.88 g + 3 x 15.99 g = 159.65 g / mol
Then, one mole of Fe2O3 has a mass of 159.65 grams.
2- Then, the relationship between the Fe2O3 that will react and the iron to be produced. With the previous calculation, we can say that with one mole of Fe2O3, two moles of Fe can be produced. Passing this relationship to the molar masses, it would be as follows:
1 mole of Fe2O3_____ 2 moles of Fe
159.65 g of Fe2O3_____ 111.76 g of Fe
3- Finally, the calculation of the mass that can be produced of Fe is made, starting from 5.50 g of Fe2O3
159.65 g of Fe2O3 _____ 111.76 g of Fe
5.50 g of Fe2O3 ______ X = 3.85 g of Fe
<em>Calculation: 5.50 g x 111.76 g / 159.65 g = 3.85 g
</em>
The answer is that 3.85 g of Fe can be produced when 5.50 g of Fe2O3 react
Answer:
Explanation:
From the given information:
TO start with the molarity of the solution:

= 0.601 mol/kg
= 0.601 m
At the freezing point, the depression of the solution is 

Using the depression in freezing point, the molar depression constant of the solvent 


The freezing point of the solution 

The molality of the solution is:

Molar depression constant of solvent X, 
Hence, using the elevation in boiling point;
the Vant'Hoff factor 


The H3O+ concentration of the solution with a PH of 3.60 is 2.5 x10^-4 M (answer A)
<u><em>explanation</em></u>
PH is calculated using PH = - log [ H3O+] formula
Therefore - log [H3O+] = 3.60
To calculate the concentration of h3O+ ,find the antilog of 3.60
Since -log is at base of 10, the antilog of 3.60 = 10^-3.60 = 2.5 x10^-4M
Answer:
2.6 kJ
Explanation:
The formula for the amount of heat (q) absorbed by the water is
q = mCΔT
1. Calculate ΔT
ΔT = 23.5 °C - 22.1 °C = 1.4 °C
2. Calculate q
q₂ = mCΔT = 500 g × 4.184 J·°C⁻¹g⁻¹ × 1.4 °C = 2900 J = 2.9 kJ