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krek1111 [17]
3 years ago
13

Magicians often use ‘flash powder’ in their acts. Flash powder contains 69.0% potassium chlorate (31.9% K, 28.9% Cl, 39.2% O) an

d the remainder is aluminium. Calculate the percentage composition by mass of each element in flash powder
Chemistry
1 answer:
mafiozo [28]3 years ago
7 0

Answer:

\rm K: approximately 22.0\%.

\rm Cl: approximately 19.9\%.

\rm O: approximately 27.0\%.

\rm Al: 31.0\%.

Explanation:

Consider a 100\; \rm g sample. There would be 69.0\% \times 100\; \rm g = 69.0\; \rm g of \rm KClO_{3} and 100.0\; \rm g - 69.0\; \rm g = 31.0\; \rm g of \rm Al.

Out of that 69.0\; \rm g of \rm KClO_{3}:

31.9\% (by mass) would be \rm K: 31.9\% \times 69.0\; \rm g \approx 22.0\; \rm g.

28.9\% (by mass) would be \rm Cl: 28.9\% \times 69.0\; \rm g \approx 19.9\; \rm g.

39.2\% (by mass) would be \rm O: 39.2\% \times 69.0\; \rm g \approx 27.0\; \rm g.

Overall, the composition (by mass) of each element in this mixture would be:

\rm K:

\begin{aligned} & \frac{31.9\% \times 69.0\; \rm g}{100\; \rm g} \\ =\; & 31.9\% \times 69.0\% \\ \approx \; & 22.0\%\end{aligned}.

\rm Cl:

\begin{aligned} & \frac{28.9\% \times 69.0\; \rm g}{100\; \rm g} \\ =\; & 28.9\% \times 69.0\% \\ \approx \; & 19.9\%\end{aligned}.

\rm O:

\begin{aligned} & \frac{39.2\% \times 69.0\; \rm g}{100\; \rm g} \\ =\; & 39.2\% \times 69.0\% \\ \approx \; & 27.0\%\end{aligned}.

\rm Al:

\begin{aligned}& \frac{100\; \rm g - 69.0\; \rm g}{100\; \rm g} \\ =\; & 100\% - 69.0\% \\ =\; & 31.0\%\end{aligned}.

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