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Ronch [10]
3 years ago
11

Identify the type of bonding within each substance. Co ( s ) ionic covalent metallic CoCl 2 ( s ) covalent ionic metallic CCl 4

( l ) metallic covalent ionic
Chemistry
1 answer:
krok68 [10]3 years ago
6 0

Answer:

1. Co ( s ) - metallic bonding

2. CoCl₂ ( s ) - ionic bonding

3. CCl₄ ( l ) - covalent bonding

Explanation:

Metallic bonding -

It is the type of bonding present between the atoms of the metals , via the electrostatic interaction between the metal and the delocalized electrons , is known as metallic bonding .

For example ,

Mostly metals show metallic bonding .

Ionic bonding -

It is the type of bonding present between the ions i.e. , the cation and the anion is known as ionic bonding .

For example ,

Mostly ionic compound , like salts show ionic bonding .

Covalent bonding -

It is the type of bonding which is present between shared pair of electrons , is known as covalent bonding .

For example ,

Most of the carbon compounds are capable to show covalent bonding .

Hence , from the question ,

1. Co ( s ) - metallic bonding

2. CoCl₂ ( s ) - ionic bonding

3. CCl₄ ( l ) - covalent bonding  

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agasfer [191]
They are examples of elements.
3 0
2 years ago
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Calculate ΔG o for the following reaction at 25°C: 3Mg(s) + 2Al3+(aq) ⇌ 3Mg2+(aq) + 2Al(s) Enter your answer in scientific notat
larisa [96]

Answer:

-3.7771 × 10² kJ/mol

Explanation:

Let's consider the following equation.

3 Mg(s) + 2 Al³⁺(aq) ⇌ 3 Mg²⁺(aq) + 2 Al(s)

We can calculate the standard Gibbs free energy (ΔG°) using the following expression.

ΔG° = ∑np . ΔG°f(p) - ∑nr . ΔG°f(r)

where,

n: moles

ΔG°f(): standard Gibbs free energy of formation

p: products

r: reactants

ΔG° = 3 mol × ΔG°f(Mg²⁺(aq)) + 2 mol × ΔG°f(Al(s)) - 3 mol × ΔG°f(Mg(s)) - 2 mol × ΔG°f(Al³⁺(aq))

ΔG° = 3 mol × (-456.35 kJ/mol) + 2 mol × 0 kJ/mol - 3 mol × 0 kJ/mol - 2 mol × (-495.67 kJ/mol)

ΔG° = -377.71 kJ = -3.7771 × 10² kJ

This is the standard Gibbs free energy per mole of reaction.

5 0
3 years ago
A student measures the pressure and volume of an empty water bottle to be 1. 4 atm and 2. 3 l
rewona [7]

The new volume of the bottle is 5.07 L.

<h3>What is Boyle's Law?</h3>

It is a gas law that states the pressure decrease with the increase in the pressure.

By the formula

\rm P_1V_1= P_1V_2

Given that, volume1 is 2.3l

Pressure1 is 4 atm.

Pressure2 to 0.65 atm.

V2 is to find?

Putting the values in the equation

\rm 1.4\times 2.3 = 0.65 \times V_2\\\\V_2 = 5.07 L

Thus, the new volume of the bottle is 5.07 L.

Learn more about Boyle's Law

brainly.com/question/1437490

#SPJ4

6 0
1 year ago
How many hours will it take for the concentration of methyl isonitrile to drop to 14.0 %% of its initial value?
tiny-mole [99]

This is an incomplete question, here is a complete question.

The rearrangement of methyl isonitrile (CH₃NC) to acetonitrile (CH₃NC) is a first-order reaction and has a rate constant of 5.11 × 10⁻⁵ s⁻¹ at 472 K. If the initial concentration of CH₃NC is 3.00 × 10⁻² M :

How many hours will it take for the concentration of methyl isonitrile to drop to 14.0 % of its initial value?

Answer : The time taken will be, 10.7 hours

Explanation :

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 5.11\times 10^{-5}s^{-1}

t = time passed by the sample  = ?

a = let initial amount of the reactant  = 100

a - x = amount left after decay process = 14 % of 100 = 14

Now put all the given values in above equation, we get

t=\frac{2.303}{5.11\times 10^{-5}}\log\frac{100}{14}

t=38482.72s=\frac{38482.72}{3600}=10.7hr

Therefore, the time taken will be, 10.7 hours

7 0
3 years ago
Which one is correct for number 6 I can’t decide
nadezda [96]

I'm pretty sure it's D .

5 0
3 years ago
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