Are controlled substances and illegal drugs the same thing?

Chemistry

2 answers:

Reil [10]3 years ago

8 0

Well i do think they're the same.

SVETLANKA909090 [29]3 years ago

4 0

No: A controlled substance is a chemical compound that is "controlled," per say, by the government. Access to these substances is limited, hence the use of prescriptions for potentially addictive pharmaceuticals.
An illegal drug is a substance deemed harmful, both to the body of one using said substance and those in the society around it, and its use is, therefore, not allowed under the law.

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What is the IUPAC name of this compund?

mr_godi [17]

Answer:

3-ethyl-4-methyl Heptane

Explanation:

longest chain is straight .

we start assigning number from where we are close to the branch to this mean its from left hand side. and we saw two chain 1 is ethyl and other is methyl . In alphabetical order e comes first as compare to m so we write ethyl first after that methyl and than in last we write longest chain name with ane (bcz we only have single vonds).

4 0

3 years ago

Read 2 more answers

For the following reaction, KP = 0.455 at 945°C: At equilibrium, is 1.78 atm. What is the equilibrium partial pressure of CH4 in

Alborosie

Answer:

See explanation below

Explanation:

The question is incomplete. However, here's the missing part of the question:

<em>"For the following reaction, Kp = 0.455 at 945 °C: </em>

<em>At equilibrium the partial pressure of H2 is 1.78 atm. What is the equilibrium partial pressure of CH4(g)?"</em>

With these question, and knowing the value of equilibrium of this reaction we can calculate the partial pressure of CH4.

The expression of Kp for this reaction is:

Kp = PpCH4 / (PpH2)²

We know the value of Kp and pressure of hydrogen, so, let's solve for CH4:

PpCH4 = Kp * PpH2²

*: You should note that we don't use Carbon here, because it's solid, and solids and liquids do not contribute in the expression of equilibrium, mainly because their concentration is constant and near to 1.

Now solving for PpCH4:

PpCH4 = 0.455 * (1.78)²

6 0

3 years ago

Octane has a density of .692 g/mL at 20 degrees C. How many grams of O2 are required to burn 19.0 gal of C8H18?

madreJ [45]

3.64 hope that helps you

8 0

3 years ago

Calculate the mole fraction of each component in a solution of 42 g CH3OH, 35 g of chloroform CHCl3, and 50 g C3H7OH

koban [17]

Considering the definition of mole fraction, the mole fraction of each component in the solution is:

CH₃OH: 0.54
CHCl₃: 0.118
C₃H₇OH: 0.342

<h3>Mole fraction</h3>

The molar fraction is a way of measuring the concentration that expresses the proportion in which a substance is found with respect to the total moles of the solution.

<h3>Mole fraction of each component</h3>

In this case, in first place you should know that the molar mass of each component is: