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3 years ago

Why do scientists need a universal system to classify organisms?

Chemistry

1 answer:

sergejj [24]3 years ago

5 0

Answer:

classification enables scientists to explain the relationships between organisms, which is helpful in trying to reconstruct the evolutionary roots of a particular species. Finally, taxonomic names provide unique descriptive names for organisms. This is sometimes an issue with common names of animals.

Explanation:

Found in the Internet

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How to write equations and show units for the Total joules gained by water for the Pringle and the Total Joules per gram of food

Paraphin [41]

Answers:

1. 7500 J; 3800 J/g

Step-by-step explanation:

1. Joules gained by water

q = mcΔT

Data:

m = 100 g

C = 4.184 J·°C⁻¹g⁻¹

ΔT = 18 °C

Calculation:

q = 100 × 4.184 × 18 =7500 J

2. Joules per gram of Pringle

Energy gained by water = energy lost by Pringle

q = -mΔH

7500 J = -1.984 g × ΔH

ΔH = -7500 J/1.984 g = -3800 J/g

Pringles contain 3800 J of food energy per gram.

7 0

3 years ago

2. Suggest four ways in which the concentration of PH3 could be increased in an equilibrium described by the following equation:

Nesterboy [21]

Answer

increase in temperature

decrease in pressure

continuous removal of PH3
adding more of P into the system

Explanation:

In the reaction P4(g)+6H2(g) ⇌ 4PH3(g);

The effect of temperature on equilibrium has to do with the heat of reaction. Recall that for an endothermic reaction, heat is absorbed in the reaction, and the value of ΔH is positive. Thus, for an endothermic reaction, we can picture heat as being a reactant:

heat+A⇌BΔH=+

Since the reaction is endothermic reaction, heat is a absorbed. Decreasing the temperature will shift the equilibrium to the left, while increasing the temperature will shift the equilibrium to the right forming more of PH3.

According to Le Chatelier’s principle, adding additional reactant to a system will shift the equilibrium to the right, towards the side of the products. In the same Way, reducing the concentration of the product will also shift equilibrium to the right continually forming PH3 as it is removed.

4 0

3 years ago

I need help with this please

ELEN [110]

Answer:

I thinkk its B. that its greater. Sry if im wrong

6 0

3 years ago

Read 2 more answers

What is the concentration of a stock solution if 20 mL was used to make 400 mL of a 1.44

timofeeve [1]

Given :

Volume of stock solution, $V_s = 20\ mL$ .

Volume of diluted solution, $V_d = 400 \ mL$ .

Molarity of diluted solution, $M_d = 1.44\ M$ .

To Find :

The concentration of the stock solution.

Solution :

We know, dilution factor is given by :

$D.F=\dfrac{V_ {diluted}}{V_{stock}}$ ....1)

and $D.F= \dfrac{M_{stock}}{M_{diluted}}$ ....2)

Putting volume in above equation, we get :

D.F = 400/20

D.F = 20

Putting value of D.F in equation 2) we get :

$\dfrac{M_{stock}}{M_{diluted}} = 20\\\\M_{stock} = 20\times 1.44\\\\M_{stock} =28.8\ M$

The concentration of stock solution is nearest to 30 M.

Therefore, the correct option is 1) 30 M.

4 0

3 years ago

Convert 3.01€22 molecules of O²(a) mole of O²) ,volume at S.T.P,no of Oxygen atom. (d) mass

Marat540 [252]

Answer:

a )0.05 moles of O₂

b) 1.1207 dm³

c) 0.3× 10²³ atoms of oxygen

d) 1.6 g

Explanation:

Given data:

Number of molecules of O₂ = 3.01 × 10²² molecules

Number of moles of O₂ = ?

Volume of oxygen at ATP = ?

Number of oxygen atoms = ?

Mass of oxygen = ?

Solution:

The given problem will solve by using Avogadro number.

"It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance". The number 6.022 × 10²³ is called Avogadro number.

Moles of oxygen:

1 mole = 6.022 × 10²³ molecules

3.01 × 10²² molecules × 1 mol / 6.022 × 10²³ molecules

0.05 moles of O₂

Number of atoms of oxygen:

1 mole = 6.022 × 10²³ atoms

0.05 mol × 6.022 × 10²³ atoms /1 mol

0.3× 10²³ atoms of oxygen

Volume of oxygen:

1 mole of oxygen at STP occupy 22.414 dm³

0.05 mol × 22.414 dm³ / 1mol

1.1207 dm³

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 0.05 mol × 32 g/mol

Mass = 1.6 g

8 0

3 years ago