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Andrews [41]
3 years ago
8

Can chopper be changed to gold? Explain​

Chemistry
1 answer:
Firlakuza [10]3 years ago
7 0

Answer:

A team of Chinese researchers have turned cheap copper into a new material “almost identical” to gold, according to a study published in peer-reviewed journal Science Advances on Saturday. The fast-moving ionized particles blasted copper atoms off the target.

hope this helps

have a good day :)

Explanation:

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Chemical properties of matter can only be observed and measured by performing a chemical change.
- Density and boiling are not chemical changes.
- This leaves reactivity and combustion. Reactivity does not need to be observed at STP so the statement is wrong.

Combustion is the best answer. 

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The number of ions produced when a substance dissolves is always equal to the number of Adams in a chemical formula. What is inc
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If the valence electrons were removed, what would be the ion charge of the element?
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Name the ions in water acidified with dilute sulphuric acid
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The rate of formation of C in the reaction 2 A + B →2 C + 3 D is 2.7 mol dm−3 s −1 . State the reaction rate, and the rates of f
Zielflug [23.3K]

Answer:

Rate of reaction =1.35mol.dm^{-3}.s^{-1}

Rate of consumption of A = 2.7mol.dm^{-3}.s^{-1}

Rate of consumption of B = 1.35mol.dm^{-3}.s^{-1}

Rate of formation of D = 4.15mol.dm^{-3}.s^{-1}

Explanation:

According to laws of mass action for the given reaction,

Rate= -\frac{1}{2}\frac{\Delta [A]}{\Delta t}=-\frac{\Delta [B]}{\Delta t}=\frac{1}{2}\frac{\Delta [C]}{\Delta t}=\frac{1}{3}\frac{\Delta [D]}{\Delta t}

where, -\frac{\Delta [A]}{\Delta t} is rate of consumption of A, -\frac{\Delta [B]}{\Delta t} is rate of consumption of B, \frac{\Delta [C]}{\Delta t} is rate of formation of C and \frac{\Delta [D]}{\Delta t} is rate of formation of D

Here \frac{\Delta [C]}{\Delta t}=2.7mol.dm^{-3}.s^{-1}

So, Rate of reaction = (\frac{1}{2}\times 2.7mol.dm^{-3}.s^{-1})=1.35mol.dm^{-3}.s^{-1}

Rate of formation of D = (\frac{3}{2}\times \frac{\Delta [C]}{\Delta t})=(\frac{3}{2}\times 2.7mol.dm^{-3}.s^{-1})=4.15mol.dm^{-3}.s^{-1}

Rate of consumption of A = (\frac{2}{2}\times \frac{\Delta [C]}{\Delta t})=(\frac{2}{2}\times 2.7mol.dm^{-3}.s^{-1})=2.7mol.dm^{-3}.s^{-1}

Rate of consumption of B = (\frac{1}{2}\times \frac{\Delta [C]}{\Delta t})=(\frac{1}{2}\times 2.7mol.dm^{-3}.s^{-1})=1.35mol.dm^{-3}.s^{-1}

3 0
3 years ago
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