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3 years ago

12

In a survey of 600 homeowners with high-speed Internet, the average monthly cost of a high-speed Internet plan was $64.20 with s

tandard deviation $11.77, estimate the number of Internet plans whose cost is:
greater than $52.43

less than $87.74

between $52.43 and $64.20

1 answer:

Dmitrij [34]3 years ago

8 0

Less than $87.74 hope that help the number is $75.97

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In a bike race Tim rode 7 1/4 miles his teammate Bill rode 8 7/8 how many miles did they ride in all

Minchanka [31]

So you add the miles together and you would get 16 1/8 you add the whole numbers and get 15. you have to change the denominator to equal the same thing so it would change to 2/8 instead of 1/4 and then add it up and get 9/8 so you add a whole number and left with 1/8 and the answer is 16 1/8

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2 years ago

-6(-2x² + 6-3w²)<br><br>they said to remove the parenthesis using distributive property helpp me

svetoff [14.1K]

Answer:

=18w2+12x2−36

Step-by-step explanation:

I hope this helps you

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2 years ago

Read 2 more answers

How did u get ur answer to this question

Sergeeva-Olga [200]

You have to find the cube root of 27.
A same number when multiplied 3 times by itself will give the cube.
3√27 = 3 x 3 x 3

So the answer is 3

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3 years ago

Find three consecutive EVEN integers such that the sum of the smallest number and twice the middle number is 20 more than the la

nordsb [41]

define the 3 numbers

smallest number = x

middle number = x + 2

largest number = x + 4

write the equation

sum of the smallest number and twice the middle number

$\begin{gathered} x+2(x+2) \\ x+2x+4 \\ 3x+4 \end{gathered}$

20 more than the largest number

$\begin{gathered} x+4+20 \\ x+24 \end{gathered}$

equal the expressions

$\begin{gathered} 3x+4=x+24 \\ 3x-x=24-4 \\ 2x=20 \\ x=\frac{20}{2} \\ x=10 \end{gathered}$

the numbers should be 10, 12 and 14

$\begin{gathered} 10+2\cdot(12)=14+20 \\ 10+24=34 \\ 34=34 \end{gathered}$

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9 months ago

Al factorizar el trinomio cuadrado perfecto, obtenemos el siguiente resultado: (que no se como resolver) xd algun pro que sepa r

PolarNik [594]

Answer:

$\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2$

Step-by-step explanation:

<u>Trinomio Cuadrado Perfecto</u>

El producto notable llamado cuadrado de un binomio se expresa como:

$(a-b)^2=a^2-2ab+b^2$

Si se tiene un trinomio, es posible convertirlo en un cuadrado perfecto si cumple con las condiciones impuestas en la fórmula:

* El primer término es un cuadrado perfecto

* El último término es un cuadrado perfecto

* El segundo término es el doble del proudcto de los dos términos del binomio.

Tenemos la expresión:

$\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8$

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

$\displaystyle a=\sqrt{\frac{100}{81}m^8p^{12}q^{16}z^2}$

$\displaystyle a=\frac{10}{9}m^4p^{6}q^{8}z$

Calculamos el valor de a como la raiz cuadrada del primer término del trinomio:

$\displaystyle b=\sqrt{\frac{1}{49}m^2p^2z^8$

$\displaystyle b=\frac{1}{7}mpz^4$

Nos cercioramos de que el término central es 2ab:

$\displaystyle 2ab=2\frac{10}{9}m^4p^{6}q^{8}z\frac{1}{7}mpz^4$

Operando:

$\displaystyle 2ab=\frac{20}{63}m^5p^7q^8z^5$

Una vez verificado, ahora podemos decir que:

$\displaystyle \frac{100}{81}m^8p^{12}q^{16}z^2-\frac{20}{63}m^5p^7q^8z^5+ \frac{1}{49}m^2p^2z^8=\left(\frac{10}{9}m^4p^{6}q^{8}z-\frac{1}{7}mpz^4\right)^2$

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2 years ago