Ek = 1/2 mv^2
9 × 10^4 = 1/2 × 800 × v^2
9 × 10^4/400 = 400 v^2 / 400
9 × 10^4/400 = v^2
√225 = v
15 ms⁻¹ = v
That's the only way I know how to work it out
I think in this case velocity and speed would be considered the same because me
s = d/t and v=d/t
one is distance travelled and the other is displacement of a body
Mass is Kg
Mol is the amount of substance
m is for meters
Answer:
255 m
Explanation:
The car is moving by uniform motion (constant velocity), so we can calculate the distance it travels by using the equation
where
d is the distance travelled
v is the velocity of the car
t is the time interval
In this problem:
v = 7.5 m/s is the velocity of the car
t = 34 s is the time interval
Therefore, the distance covered by the car is
Answer:
-0.0426 m
Explanation:
-i / o = h' / h
-1.71 / 0.0237 = 3.04 /o
o = -0.042
1/o + 1/i = 1/f
1/(-0.042) + 1/(3.04) = 1/f
-23.81 +0.329 = 1/f
-23.481 = 1/f
f = -0.0426 m