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olga_2 [115]
2 years ago
13

Boxes are transported from one location to another in a warehouse by means of a conveyor belt that moves with a constant speed o

f 0.56 m/s. At a certain location the conveyor belt moves for 2.0 m up an incline that makes an angle of 15° with the horizontal. Assume that a 2.1 kg box rides on the belt without slipping. At what rate is the force of the conveyor belt doing work on the box as the box moves up the 15° incline?
Physics
1 answer:
krek1111 [17]2 years ago
6 0

Answer:

P = 15.90 W

Explanation:

given,

speed of conveyor belt = 0.56 m/s

conveyor belt move up to = 2 m      

angle made with the horizontal = 15°

mass of the box = 2.1 kg                      

rate is the force of the conveyor belt doing work on the box as the box moves up                                                  

P = F v cos ∅

P = 3 × 9.8 × 0.56 × cos 15°

P = 15.90 W

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Answer:

An Oven

Explanation:

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6 0
3 years ago
If riding a lawnmower engine exerts 19 hp in one minute to move the lawnmower how much work is done
ioda

Answer:

the work done by the lawnmower is 236.14 J.

Explanation:

Given;

power exerted by the lawnmower engine, P = 19 hp

time in which the power was exerted, t = 1 minute = 60 s.

1 hp = 745.7 watts

The work done by the lawnmower is calculated as follows;

Work = Energy = \frac{Power}{time} \\\\Work = \frac{(19 \times 745.7)}{60} = 236.14 \ J

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6 0
3 years ago
Using Rayleigh's criterion, what is the smallest separation between two pointlike objects that a person could clearly resolve at
atroni [7]

 Answer:

y = 52.44 10⁻⁶  m

Explanation:

It is Rayleigh's principle that two points are resolved if the maximum of the diffraction pattern of one matches the minimum the diffraction pattern of the other

Based on this principle we must find the angle of the first minimum of the diffraction expression

         a sin θ= m λ

The first minimum occurs for m = 1

       sin θ =  λ  / a

Now let's use trigonometry the object is a distance L = 0.205 m

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Since the angles are very small, let's approximate

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We substitute in the diffraction equation

         y / L =  λ  / a

         y =  λ  L / a

Let's calculate

        y = 550 10⁻⁹ 0.205 / 2.15 10⁻³

        y = 52.44 10⁻⁶ m

7 0
3 years ago
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Answer:

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3 years ago
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2 years ago
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