Answer:
2.9 m/s
Explanation:
Momentum will be conserved
Speed of the ball just before collision is
v = √2gh = √(2(9.8)(0.8)) = 3.96 m/s
The initial momentum is 1.3(3.96) = 5.15 kg•m/s
The block takes away momentum of 0.6(2.2) = 1.32 kg•m/s
Leaving the ball with momentum of 5.15 - 1.32 = 3.83 kg•m/s
vf(ball) = 3.83 / 1.3 = 2.946... ≈ 2.9 m/s
50 degrees because the would most likely equal out
+ 1.58 e -15
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The choice that is most likely end for a star that formed from an extremely large nebula would be a black hole. Gravity pulls so much in a black hole that no light exists.
