C: Litmus Paper. Red litmus paper turns blue in acids; blue litmus paper turns red in bases
Answer:
Net displacement = 0
Distance traveled = 2PQ <_up and down
Explanation:
Answer:
w= 62.75 J
Explanation:
Given that
Force vector F= 5 x i + 4 y j
Space vector or displacement vector d= 5.01 i
We know that work (w)
w=∫ F.ds
w= ∫(5 x i + 4 y j) .dx ( only object is moving in x- direction)


![w=\left [\dfrac{5}{2}x^2\right ]_0^{5.01}](https://tex.z-dn.net/?f=w%3D%5Cleft%20%5B%5Cdfrac%7B5%7D%7B2%7Dx%5E2%5Cright%20%5D_0%5E%7B5.01%7D)
w= 2.5 x 5.01² J
w= 62.75 J
Answer:
the person will be in the shore at 10.73 minutes after launch the shoe.
Explanation:
For this we will use the law of the lineal momentum.

Also,
L = MV
where M is de mass and V the velocity.
replacing,

wher Mi y Vi are the initial mass and velocity, Mfp y Vfp are the final mass and velocity of the person and Mfz y Vfz are the final mass and velocity of the shoe.
so, we will take the direction where be launched the shoe as negative. then:
(70)(0) = (70-0.175)(
) + (0.175)(-3.2m/s)
solving for
,
= 
= 0.008m/s
for know when the person will be in the shore we will use the rule of three as:
1 second -------------- 0.008m
t seconds-------------- 5.15m
solving for t,
t = 5.15m/0.008m
t = 643.75 seconds = 10.73 minutes
<span>Three-fourths of the illuminated side of the moon be visible
from Earth when the moon is at position-B. (choice-B)
Notice the particularly egregious screw-up on the drawing at the
"Third Quarter" position. There, the drawing shows the illuminated
side of the moon AWAY from the sun, and the dark side of the moon
TOWARD the sun. That's about as silly as you can get. </span>