A passenger at the rear of a train traveling at 15 m/s relative to earth throws a baseball with a speed of 15 m/s in the directi
1 answer:
Answer:
0 m/s
Explanation:
Let's take the direction in which the train is travelling as positive direction. Therefore:
- The velocity of the train with respect to earth is:
- The ball is thrown with speed 15 m/s in the opposite direction, so in the frame of reference of the train, its velocity is
Therefore, the velocity of the baseball in the earth's reference frame will be the algebraic sum of these two velocities, so:
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Answer:
w= 62.75 J
Explanation:
Given that
Force vector F= 5 x i + 4 y j
Space vector or displacement vector d= 5.01 i
We know that work (w)
w=∫ F.ds
w= ∫(5 x i + 4 y j) .dx ( only object is moving in x- direction)
w= 2.5 x 5.01² J
w= 62.75 J
Answer:
the person will be in the shore at 10.73 minutes after launch the shoe.
Explanation:
For this we will use the law of the lineal momentum.
Also,
L = MV
where M is de mass and V the velocity.
replacing,
wher Mi y Vi are the initial mass and velocity, Mfp y Vfp are the final mass and velocity of the person and Mfz y Vfz are the final mass and velocity of the shoe.
so, we will take the direction where be launched the shoe as negative. then:
(70)(0) = (70-0.175)() + (0.175)(-3.2m/s)
solving for ,
=
= 0.008m/s
for know when the person will be in the shore we will use the rule of three as:
1 second -------------- 0.008m
t seconds-------------- 5.15m
solving for t,
t = 5.15m/0.008m
t = 643.75 seconds = 10.73 minutes