A passenger at the rear of a train traveling at 15 m/s relative to earth throws a baseball with a speed of 15 m/s in the directi
1 answer:
Answer:
0 m/s
Explanation:
Let's take the direction in which the train is travelling as positive direction. Therefore:
- The velocity of the train with respect to earth is:
- The ball is thrown with speed 15 m/s in the opposite direction, so in the frame of reference of the train, its velocity is
Therefore, the velocity of the baseball in the earth's reference frame will be the algebraic sum of these two velocities, so:
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Answer:
a = 3.125 [m/s^2]
Explanation:
In order to solve this problem, we must use the following equation of kinematics. But first, we have to convert the speed of 90 [km/h] to meters per second.
where:
Vf = final velocity = 25 [m/s]
Vi = initial velocity = 0
a = acceleration [m/s^2]
t = time = 8 [s]
The initial speed is zero as the bus starts to koverse from rest. The positive sign of the equation means that the bus increases its speed.
25 = 0 + a*8
a = 3.125 [m/s^2]