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3 years ago

Iron sulfide is a compound. It is made by heating a mixture of iron and sulfur.

Chemistry

1 answer:

lara [203]3 years ago

6 0

Answer:

Here are some of the differences between a mixture of iron and sulfur, and iron sulfide: the mixture can contain more or less iron, but iron sulfide always contains equal amounts of iron and sulfur. the iron and sulfur atoms are not joined together in the mixture, but they are joined together in iron sulfide.

Explanation:

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Why is carbone reduction process not applied for the extraction of alkali

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Carbon cannot reduce sodium because sodium is stronger than carbon. reactive metals like sodium and potassium and electrolysis has to be used.

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3 years ago

How many grams of CO are needed to react with an excess of Fe2O3 to produce (210.3 g Fe) 209.7 g Fe? Show your work.

Fed [463]

Explanation:

$3CO(g)+Fe_2O_3(s)\rightarrow 2Fe(s)+3CO_2(g)$

1)Mass of CO when 210.3 g of Fe produced.

Number of moles of $Fe$ in 210.3 g=

$\frac{\text{Given mass of Fe}}{\text{Molar mass of Fe}}$

$=\frac{210.3}{55.84 g/mol}=3.76 mol$

According to reaction, 2 moles of Fe are obtained from 3 moles of CO, then 3.76 moles of Fe will be obtained from : $\frac{3}{2}\times 3.76 moles$ of CO that is 5.64 moles.

Mass of CO in 5.64 moles =

$\text{Number of moles}\times \text{molar mass of CO}=5.46\times 28 g/mol=157.92 g$

2)Mass of CO when 209.7 g of Fe produced.

Number of moles of $Fe$ in 209.7 g=

$\frac{\text{Given mass of Fe}}{\text{Molar mass of Fe}}$

$=\frac{209.7}{55.84 g/mol}=3.75 mol$

According to reaction, 2 moles of Fe are obtained from 3 moles of CO, then 3.75 moles of Fe will be obtained from : $\frac{3}{2}\times 3.75 moles$ of CO that is 5.625 moles.

Mass of CO in 5.625 moles =

$\text{Number of moles}\times \text{molar mass of CO}=5.625\times 28 g/mol=157.5 g$

4 0

3 years ago

Read 2 more answers

A single atom of an element has 11 protons, 11 electrons, and 12 neutrons. Which element is it?

nataly862011 [7]

Answer:

Explanation:

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3 years ago

15.0 g of Fe and 25.0 g of sand are added to 250.0 g of water. a. Determine the percent mass of Fe, sand, and water in the mixtu

lana [24]

Answer:

A. percentage mass of iron = 5.17%

percentage mass of sand = 8.62%

percentage mass of water = 86.205%

B. (Iron + sand + water) -------> ( iron + sand) ------> sand

C. The step of separation of iron and sand

Explanation:

A. Percentage mass of the mixtures:

Total mass of mixture = (15.0 + 25.0 + 250.0) g =290.0 g

percentage mass of iron = 15/290 * 100% = 5.17%

percentage mass of sand = 25/290 * 100% = 8.62%

percentage mass of water = 250/290 * 100% = 86.205%

B. Flow chart of separation procedure

(Iron + sand + water) -------> separation by filtration using filter paper and funnel to remove water --------> ( iron + sand) -----------> separation using magnet to remove iron ------> sand

C. The step of separation of iron and sand by magnetization of iron will have the highest amount of error because during the process, some iron particles may not readily be attracted to the magnet as they may have become interlaced in-between sand grains. Also, some sand particle may also be attracted to the magnet as they are are borne on iron particles.

5 0

3 years ago

Is iornIInitrate ionic or covalent

kondaur [170]

Answer:

Iron (II) nitrate is ionic compound

Explanation:

Formula:

Fe(NO₃)₂

Iron (II) nitrate is ionic compound.

Its molecular mass is 179.85 g/mol.

NO⁻₃ is anion while Fe⁺² is cation.

Iron loses its two electron which is accepted by nitrate.

Its molecular formula can be written as FeN₂O₆.

Its color is pale green.

Its melting point is 333.65 K.

It is para magnetic compound.

it is mostly present in non hydrated form.

It is also known as ferric nitrate.

It is used to form sodium amide.

Its is also used catalyst.

7 0

3 years ago