Answer:
Most likely true
Explanation:
because the speed of all ocean waves is controlled by gravity, wavelength, and water depth. ... Waves moving through water deeper than half their wavelength are known as deep-water waves. On the other hand, the orbits of water molecules in waves moving through shallow water are flattened by the proximity of the sea surface bottom.
Explanation:
P1V1 = nRT1
P2V2 = nRT2
Divide one by the other:
P1V1/P2V2 = nRT1/nRT2
From which:
P1V1/P2V2 = T1/T2
(Or P1V1 = P2V2 under isothermal conditions)
Inverting and isolating T2 (final temp)
(P2V2/P1V1)T1 = T2 (Temp in K).
Now P1/P2 = 1
V1/V2 = 1/2
T1 = 273 K, the initial temp.
Therefore, inserting these values into above:
2 x 273 K = T2 = 546 K, or 273 C.
Thus, increasing the temperature to 273 C from 0C doubles its volume, assuming ideal gas behaviour. This result could have been inferred from the fact that the the volume vs temperature line above the boiling temperature of the gas would theoretically have passed through the origin (0 K) which means that a doubling of temperature at any temperature above the bp of the gas, doubles the volume.
From the ideal gas equation:
V = nRT/P or at constant pressure:
V = kT where the constant k = nR/P. Therefore, theoretically, at 0 K the volume is zero. Of course, in practice that would not happen since a very small percentage of the volume would be taken up by the solidified gas.
Answer:a) Mass of 
in mixture = 26.3 grams
b) Mass of 
in mixture that can be recovered= 21.5 grams
Explanation:
Given :
Total Pressure = pressure of krypton + pressure of carbon dioxide = 0.751 atm
pressure of krypton = 0.231 atm
Thus pressure of carbon dioxide = 0.751 - 0.231 =0.52 atm
As we know:
where,
= partial pressure
= total pressure = 0.751 atm
= mole fraction
For
For
Total mass = Mass of + Mass of krypton = 30.8 + 25.2 = 56 g
Percentage of 
a) Thus Mass of in mixture =
Percentage of 
b) Thus Mass of in mixture that can be recovered=
