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Allisa [31]
3 years ago
15

What type of triangle measures 8 inches,8 inches,3 inches

Physics
2 answers:
kykrilka [37]3 years ago
7 0

Answer:

isoceles

Explanation:

Because two sides are equal

Pachacha [2.7K]3 years ago
4 0

Answer:

An Isosceles triangle

Explanation:

An Isosceles triangle is a triangle where AT LEAST two sides are congruent.

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An open system starts with 52 J of mechanical energy. The energy changes
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Answer:

47 J

hope it helps u

thanks for easy ask

3 0
2 years ago
Apparent brightness depends on which two properties?
Serjik [45]

Answer:

I believe it is luminosity and distance

Explanation:

So B

6 0
3 years ago
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Hydrogen cyanide (HCN) is a product of combustion that:
bekas [8.4K]

b. is equally as toxic as carbon monoxide (CO).

Explanation:

Hydrogen Cyanide is a product of combustion that is equally as toxic as carbon monoxide CO.

The gas is a product of combustion in blast furnances, coke ovens, e.t.c

  • Just like carbon monoxide, they are blood agents that are toxic in the body
  • Prolonged exposure to hydrogen cyanide can lead to death eventually.
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Learn more:

Safety data sheets brainly.com/question/2188622

#learnwithBrainly

5 0
3 years ago
50POINTS! Find the orbital speed of a satellite in a circular orbit 1700km above the surface of the Earth. M_earth 5.97e24kg, r_
ivolga24 [154]
<h2>Answer: 7020.117 m/s</h2>

Explanation:

The velocity of a satellite describing a circular orbit is<u> constant</u> and defined by the following expression:  

V=\sqrt{G\frac{M}{R}} (1)  

Where:  

G=6.674({10}^{-11})\frac{N{m}^{2}}{{kg}^{2}} is the gravity constant

M_{Earth}=5.97{10}^{24}kg the mass of the massive body around which the satellite is orbiting, in this case, the Earth .

R=r_{Earth}+h=8080000m the radius of the orbit (measured from the center of the planet to the satellite).  

This means the radius of the orbit is equal to <u>the sum</u> of the average radius of the Earth r_{Earth} and the altitude of the satellite above the Earth's surface h.

Note this orbital speed, as well as orbital period, does not depend on the mass of the satellite. It depends on the mass of the massive body (the Earth).

Now, rewriting equation (1) with the known values:

V=\sqrt{(6.674({10}^{-11})\frac{N{m}^{2}}{{kg}^{2}})\frac{5.97{10}^{24}kg}{8080000m}}

V=7020.117\frac{m}{s}  

6 0
3 years ago
Read 2 more answers
What is the kinetic energy of a 1 kilogram ball is thrown into the air with an initial velocity of 30 m/sec
disa [49]
To find this we should use the equation Ek=1/2mv^2 where Ek is the kinetic energy, m is the mass and v is the velocity. So by this Ek=1/2*1*30^2 which then makes Ek=450 joules
5 0
2 years ago
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