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Rzqust [24]
4 years ago
6

On a beautiful fall day we see the trees' image in the pond. We can see the trees in the pond because of what property of light?

Physics
2 answers:
alexgriva [62]4 years ago
7 0

Answer:

the answer is c-reflection

Vikki [24]4 years ago
6 0
The answer is C (reflection)
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A uniform disk with a mass of 5.0 kg and diameter 30 cm rotates on a frictionless fixed axis through its center and perpendicula
igomit [66]

Answer:

Angular acceleration of the disk will be \alpha =10.714rad/sec^2

Explanation:

We have given mass of the disk m = 5 kg

Diameter of the disk d = 30 cm = 0.3 m

So radius r=\frac{d}{2}=\frac{0.3}{2}=0.15m

Moment of inertia of disk is given by I=\frac{1}{2}mr^2=\frac{1}{2}\times 5\times 0.15^2=0.056kgm^2

Force is given by F=4 N

Torque is given as \tau =Fr=4\times 0.15=0.6N-m

We also know that torque is given by \tau =I\alpha

0.6=0.056\times \alpha

\alpha =10.714rad/sec^2

5 0
3 years ago
how is the color of an object related to the wavelengths of light that are reflected and the wavelengths that are absorbed
Gekata [30.6K]

<u>The color of an object is related to the wavelengths of light that are reflected and the wavelengths that are absorbed because:</u>

Visible light is light that has wavelengths that can be detected by the human eye. The wavelength of visible light determines the color that the light appears. The light with the longest wavelength is red, and light with the shortest wavelength is violet.

An opaque object doesn’t allow light to pass through it. But, it reflects or absorbs the light that strike it. Some objects like the leaves reflect one or a few wavelengths of visible light and absorb the others. The reflected wavelengths are used to find the color of an object as it is seen by the human eye. Example: The leaves are in green as they reflect green light and absorb the other wavelengths light. A transparent or translucent material, such as window glass, transmits some or all of the light that strikes it. This means that the light passes through the material rather than being reflected by it. Hence, we see the material because of the transmitted light. So the wavelength of the transmitted light is used to find the color that the object appears.

4 0
4 years ago
Find the uncertainty in position (in nm) associated with an electron that is moving with a velocity of 572 km/s. The uncertainty
Salsk061 [2.6K]

Answer:

c

Explanation:

7 0
3 years ago
Find the orbital period (in years) of an asteroid whose average distance from the sun is 27
dmitriy555 [2]
Using Kepler's third law which is defined as the square of the average distance is directly proportional to the cube of the period. It is expressed as P^2 = a^3, Given that the a = average distance is given, the period would be much easier to compute. P = sqrt(27^3) = 140
7 0
3 years ago
In Anchorage, collisions of a vehicle with a moose are so common that they are referred to with the abbreviationMVC. Suppose a 1
lara31 [8.8K]

Answer:

Part a)

f = \frac{8}{9}

Part b)

f = \frac{120}{169}

Part c)

So from above discussion we have the result that energy loss will be more if the collision occurs with animal with more mass

Explanation:

Part a)

Let say the collision between Moose and the car is elastic collision

So here we can use momentum conservation

m_1v_{1i} = m_1v_{1f} + m_2v_{2f}

1000 v_o = 1000 v_{1f} + 500 v_{2f}

also by elastic collision condition we know that

v_{2f} - v_{1f} = v_o

now we have

2v_o = 2v_{1f} + v_o + v_{1f}

now we have

v_{1f} = \frac{v_o}{3}

Now loss in kinetic energy of the car is given as

\Delta K = \frac{1}{2}m(v_o^2 - v_{1f}^2)

\Delta K = \frac{1}{2}m(v_o^2 - \frac{v_o^2}{9})

so fractional loss in energy is given as

f = \frac{\Delta K}{K}

f = \frac{\frac{4}{9}mv_o^2}{\frac{1}{2}mv_o^2}

f = \frac{8}{9}

Part b)

Let say the collision between Camel and the car is elastic collision

So here we can use momentum conservation

m_1v_{1i} = m_1v_{1f} + m_2v_{2f}

1000 v_o = 1000 v_{1f} + 300 v_{2f}

also by elastic collision condition we know that

v_{2f} - v_{1f} = v_o

now we have

10v_o = 10v_{1f} + 3(v_o + v_{1f})

now we have

v_{1f} = \frac{7v_o}{13}

Now loss in kinetic energy of the car is given as

\Delta K = \frac{1}{2}m(v_o^2 - v_{1f}^2)

\Delta K = \frac{1}{2}m(v_o^2 - \frac{49v_o^2}{169})

so fractional loss in energy is given as

f = \frac{\Delta K}{K}

f = \frac{\frac{60}{169}mv_o^2}{\frac{1}{2}mv_o^2}

f = \frac{120}{169}

Part c)

So from above discussion we have the result that energy loss will be more if the collision occurs with animal with more mass

8 0
3 years ago
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