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Sedbober [7]
3 years ago
12

you open a can of soda room temperature and here hiss. which of the following factors has changed inside the container

Chemistry
2 answers:
stira [4]3 years ago
8 0
Do u have any options to pick from?
astra-53 [7]3 years ago
4 0

The pressure of gas

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Magnesium has three naturally occurring isotopes with masses of 23.99, 24.99, and 25.98 amu and natural abundances of 78.99%, 10
Darya [45]
Atomic mass of magnesium = (23.99 x 78.99%) + (24.99 x 10.00%) + (25.98 x 11.01%)
= 24.31 g/mol
5 0
3 years ago
Sterling silver contains silver and copper metals. if a sterling silver chain contains 17.6g of silver and 2.40g of copper, what
Bogdan [553]

Answer:-  0.88

Solution:- Masses of silver and copper metals are given and we are asked to calculate the percentage of silver in the alloy.

mass percent of Ag = (\frac{mass of Ag}{mass of alloy})*100

Mass of Ag = 17.6 g

mass of Cu = 2.40 g

mass of alloy = 17.6 g + 2.40 g = 20.0 g

Let's plug in the values in the formula:

mass percentage of Ag = (\frac{17.6}{20.0})*100

mass percentage of Ag = 88%

So, the mass percentage of silver in sterling silver is 88% and in decimal form it is 0.88.

7 0
3 years ago
The typical atmospheric pressure on top of Pikes Peak, Colorado (14109 ft. ) is 656.2 torr. Convert the pressure to :
myrzilka [38]
21.5010667479427 I goth this asnswer cause I divided I think that's how u do it
5 0
3 years ago
What does C represent
zimovet [89]

Answer: the distance of energy from point d to e

8 0
3 years ago
Read 2 more answers
(c) O2 gas is transferred from a 3 L vessel containing oxygen at 4 atm to an evacuated 20 L vessel at a constant temperature of
Fudgin [204]

Answer:

After the transfer the pressure inside the 20 L vessel is 0.6 atm.

Explanation:

Considering O2 as an ideal gas, it is at an initial state (1) with V1 = 3L and P1 = 4 atm. And a final state (2) with V2 = 20L. The temperature remain constant at all the process, thus here applies the Boyle-Mariotte law. This law establishes that at a constant temperature an ideal gas the relationship between pressure and volume remain constant at all time:

P x V = k

Therefore, for this problem the step by step explanation is:

P_{1} xV_{1} = P_{2} xV_{2}

Clearing P2 and replacing

P_{2}= \frac{P_{1} xV_{1}}{V_{2} } = \frac{4atmx3L}{20L} = 0.6atm

7 0
3 years ago
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