Answer:
A) 0.1773
B)Right electrode is the positive one
Explanation:
THIS IS THE COMPLETE QUESTION
certain metal M forms a soluble sulfate salt M S04. Suppose the left half cell of a galvanic cell apparatus is filled with a 4.50 mM solution of M2SO4 and the right half cell with a 4.50 M solution of the same substance. Electrodes made of M are dipped into both solutions and a voltmeter is connected between them. The temperature of the apparatus is held constant at 20.0 °C. O left Which electrode will be positive? Oright x 5 ? What voltage will the voltmeter show? Assume its positive lead is connected to the positive electrode. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.
EXPLANATION;
SEE THE ATTACHMENT BELOW
Consider horizontal component:
Using the formula:v2=u2+2a<span>s</span>
<span>0=(16sin<span>470</span><span>)2</span>+2(−9.81)s</span><span>s=6.98m</span><span>=7.0m(2s.f.)</span>The maximu height from the ground is 8.5m
F=ma
F=QE = 1.602e-19C*700N/C = 1.1214e-16N
1.1214e-16N = ma = 1.6726e-27kg * a
a = 6.702e10 m/s² along the direction of the field line
Answer:
The fringes are 4.7*10^-7 m apart, such that they are adjacent.
Explanation:
Using the formula for adjacent fringes given a single slit:
Δ
Δ
Δ
Hope this helps!