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Nimfa-mama [501]
3 years ago
12

What is the kinetic energy of a 1700 kg car traveling at a speed of 30 m/s (â65 mph)? does your answer to part b depend on the c

ar's mass?
Physics
1 answer:
MArishka [77]3 years ago
6 0
The kinetic energy of an object is given by
K= \frac{1}{2} mv^2
where m is the mass of the object and v its velocity.

For the car in the problem, m=1700 kg and v=30 m/s, so the kinetic energy of the car is
K= \frac{1}{2}mv^2= \frac{1}{2}(1700 kg)(30 m/s)^2=7.65\cdot 10^5 J

and as we can see, yes, the answer depends on the car's mass.
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A hot-air balloon is accelerating upward under the influence of two forces, its weight and the buoyant force. for simplicity, co
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Let V = the volume of the balloon
Force of gravity = V * ?hot * g downward
Buoyant force = V * ?cool * g upward
Net upward force F = V * ?cool * g - V * ?hot * g

F = V g (?cool - ?hot)

Mass of the balloon m = V ?hot

a = F/m = V g (?cool - ?hot)/(V ?hot)

a = g(?cool/?hot - 1)

a = 9.8(1.29/0.93 - 1)

a = 3.79 m/s^2

<span>Answer is 3.79 m/s^2</span>
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3 years ago
Which example gives all the necessary information to describe motion scientifically
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Correct option is=A because 25mph means=25miles per hour
5 0
3 years ago
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What is beach nourishment
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2 years ago
Prove that hoop stress is twice the longitudinal stress in a cylindrical pressure vessel.
Iteru [2.4K]

Answer:

Proof in explanation.

Explanation:

Consider a thin cylinder, whose thickness to diameter ration is less than 1/20, the hoop stress can be derived as follows:

Let,

L = length of cylinder

d = internal diameter of cylinder

t = thickness of wall of cylinder

P = internal pressure

σH = Hoop Stress

σL = Longitudinal Stress

Total force on half-cylinder owing to internal pressure = P x  Projected Area = P x dL    (Refer fig 9.1)

Total resisting force owing to hoop stress setup in walls = 2 σH L t

Therefore,

P d L = 2 σH L t

σH = Pd/2t      _____________ eqn (1)

Now, for longitudinal stress:

Total force on end of cylinder owing to internal pressure = P x  Projected Area = P x πd²/4

Area resisting this force = π d t        (Refer fig 9.2)

Longitudinal Stress = Force/Area

σL = (Pπd²/4)/(πdt)

σL = Pd/4t        ____________ eqn (2)

Dividing eqn (1) by eqn (2)

σH/σL = 2

<u>σH = 2 σL</u>      (Hence, Proved)

6 0
3 years ago
9. A woman runs a kilometer using a force of 210N and a power output of 500W. How
Anarel [89]

Answer:

7 minutes

Explanation:

Power = work / time

Power = force × distance / time

500 W = 210 N × 1000 m / t

t = 420 s

t = 7 min

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