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Nimfa-mama [501]
3 years ago
12

What is the kinetic energy of a 1700 kg car traveling at a speed of 30 m/s (â65 mph)? does your answer to part b depend on the c

ar's mass?
Physics
1 answer:
MArishka [77]3 years ago
6 0
The kinetic energy of an object is given by
K= \frac{1}{2} mv^2
where m is the mass of the object and v its velocity.

For the car in the problem, m=1700 kg and v=30 m/s, so the kinetic energy of the car is
K= \frac{1}{2}mv^2= \frac{1}{2}(1700 kg)(30 m/s)^2=7.65\cdot 10^5 J

and as we can see, yes, the answer depends on the car's mass.
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One of the checks that you could do for problem 1) would be to check the output resistance of the Wheatstone bridge to make sure
Ray Of Light [21]

Answer:

Explanation:

Let the four resistances of th wheat stone bridge is

P, Q, R and S and the value of each is 350 ohm.

Here, P and Q are in series.

R' = P + Q = 350 + 350 = 700 ohm

Then R and S are in series

R' = R + S = 350 + 350 = 700 ohm

Now R' and R'' are in parallel.

So, the equivalent resistance is

Req = R' x R'' / ( R' + R'')

Req = 700 / 2 = 350 ohm

Thus, the reading of ohmmeter is 350 ohm.

6 0
3 years ago
In the aftermath of an intense earthquake, the earth as a whole "rings" with a period of 54 minutes.
lawyer [7]

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The frequency of a wave is defined as the number of cycles completed per second while the period refers to the time taken to complete a cycle. The frequency is the inverse of period.

So;

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Frequency (f) = T-1 = 1/T = 1/3240 seconds = 0.00031 Hz

Learn more: brainly.com/question/14588679

6 0
2 years ago
On a playground, there is a merry‑go‑round. In order to get it moving, Bonnie applies a force of 31 N31 N . The merry‑go‑round m
nika2105 [10]

Answer:

The magnitude of the torque is 263.5 N.

Explanation:

Given that,

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We need to calculate the torque

Using formula of torque

\tau=Fd\sin\theta

Where, F = force

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Put the value into the formula

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Hence, The magnitude of the torque is 263.5 N.

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3 years ago
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