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Mashutka [201]
3 years ago
5

Write the power set of the set A={a,b,c}​

Mathematics
1 answer:
Burka [1]3 years ago
8 0

Answer:

P(A) = {{a},{b},{c},{a,b},{a,c},{b,c},{a,b,c},∅}

Step-by-step explanation:

➨ Power Set is the set of all subsets.

First, find the subset of A.

{a},{b},{c},{a,b},{a,c},{b,c},{a,b,c},∅

If you aren't sure that you already have written all subsets or not, use the following formula.

2^n ➩ where n is the number of element/members.

Our number of members are 3, use the following formula.

2^3=8

Thus, our subsets should be 8.

As we've already gathered all subsets, write the braces all whole subsets.

P(A) = {{a},{b},{c},{a,b},{a,c},{b,c},{a,b,c},∅}

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2= 5.50 4= 10.50 here is your answer 
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3 years ago
A cylindrical plastic pipe’s length is 12 cm and it’s radius is 2.5 cm. To the nearest tenth, what is the volume of the pipe?
NemiM [27]

Answer:

V = 235.6 cm³

Step-by-step explanation:

the formula for the volume of a cylinder of radius r and length h is

V = πr²h.  

Here, r = 2.5 cm and h = 12 cm, so the volume is:

V = π(2.5 cm)²(12 cm) = 75π cm³

To the nearest tenth, this volume would be V = 235.6 cm³

7 0
3 years ago
Read 2 more answers
Solve the equation 1/2(16x – 6) = 2.
Lorico [155]

Answer:

x = 0.625 or 5/8

Step-by-step explanation:

1/2(16x-6) = 2

8x - 3 = 3

8x = 3 + 3

8x/8 = 9/8

x = 0.625

can you mark me as brainliest

6 0
2 years ago
What is the common denominator for 5/8 and 1/4
Troyanec [42]

Answer:

i think the answer is 8 or it could be 2 or 4 :)

Step-by-step explanation:

5 0
2 years ago
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Write an equation of the circle that has a diameter with endpoints (12, 3) and<br> (-18,3).
Mademuasel [1]

The equation of the circle that has a diameter with endpoints (12, 3) and(-18,3) is x² + y² + 6x - 6y - 207 = 0

<h3>Coordinates of center of circle</h3>

Since the endpoints of the diameter are (x₁, y₁) = (12,3) and (x₂, y₂) = (-18,3), the coordinates of the center of the circle are the midpoints of the diameter. So, the midpoints are

  • x = (x₁ + x₂)/2 = (12 + (-18))/2 = (12 - 18)/2 = -6/2 = -3 and
  • y = (y₁ + y₂)/2 = (3 + 3)/2 = 6/2 = 3.

So, the coordinates of the center of the circle are (-3, 3)

<h3>The radius of the circle</h3>

The radius of the circle r = √[(x₁ - h)² + (y₁ - k)²] where

  • (x₁, y₁) = coordinates of end of diameter = (12, 3) and
  • (h, k) = coordinates of center of circle = (-3, 3)

So, substituting the values of the variables into r, we have

r = √[(x₁ - h)² + (y₁ - k)²]

r = √[(12 - (-3))² + (3 - 3)²]

r = √[(12 + 3)² + 0²]

r = √[15² + 0²]

r = √15²

r = 15

<h3>The equation of the circle</h3>

The equation of a circle with center (h,k) is given by

(x - h)² + (y - k)² = r² where r = radius of circle.

Substituting the values of the variables into the equation, we have

(x - h)² + (y - k)² = r²

(x - (-3))² + (y - 3)² = 15²

(x + 3)² + (y - 3)² = 15²

x² + 6x + 9 + y² - 6y + 9 = 225

x² + 6x + y² - 6y + 9 + 9 - 225 = 0

x² + y² + 6x - 6y - 207 = 0

The equation of the circle that has a diameter with endpoints (12, 3) and(-18,3) is x² + y² + 6x - 6y - 207 = 0

Learn more about equation of a circle here:

brainly.com/question/18435467

5 0
2 years ago
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