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3 years ago

AHHHHH HELP ME WITH THESE QUESTIONS FOR MY QUIZ

Chemistry

1 answer:

mash [69]3 years ago

4 0

Question 6: True

Question 7: Earth

Hope this helps :)

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Zn + 2 HCl --> ZnCl2 + H2 How many moles of hydrochloric acid (HCl) are used (assume a complete reaction) if 8.3 moles of zin

uysha [10]

Answer:

E. 16.6 mol HCl

Explanation:

The equation for the reaction is;

Zn + 2 HCl --> ZnCl2 + H2

From the reaction 2 moles of HCl produces 1 mole of ZnCl2

Therefore; 8.3 moles of ZnCl2 will be produced by;

= 8.3 moles ×2

= 16.6 Moles of HCl

Therefore; E. 16.6 mol HCl

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3 years ago

Simplify - Factor a

Dmitriy789 [7]

Answer:

Option 1

Explanation:

Option number 1 is the most compact one which indicates it is a solid

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3 years ago

Describe, on a molecular level, how you would expect these lipids to behave in water.

Gelneren [198K]

Lipids are hydrophobic; They would be insoluble, group together, and float to the top

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3 years ago

How many mL will a 0.205 mole sample of He occupy at 3.00 atm and 200 K? Report your answer to the nearest mL.

Tcecarenko [31]

1.1214 mL will a 0.205-mole sample of He occupy at 3.00 atm and 200 K.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Using equation PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 3.00 atm

V= ?

n=0.205 mole

R= $0.082057338 \;L \;atm \;K^{-1}mol^{-1}$

T=200 K

Putting value in the given equation:

$\frac{nRT}{P} =V$

$V= \frac{0.205 \;mole\;0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 200}{3 \;atm}$

V= 1.1214 mL

Learn more about the ideal gas here:

brainly.com/question/27691721

#SPJ1

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2 years ago

Please help will give 30 points.

vredina [299]

Answer:

Dependent variable: If calcium is given, then bone strength will increase.

Explanation:

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3 years ago