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3 years ago

What substance takes part in an enzymatic reaction, but is unchanged by the reaction?

1 answer:

5 0

The answer to this question would be: enzyme

Enzyme is a kind of catalyst that will take part in the chemical reaction but it won't be reacted. Enzyme only helps by reducing the energy needed to start the reaction.
Theoretically, the enzyme is not mandatory needed but if you have an enzyme the reaction will be easier, thus increasing reaction speed. But in most case, the reaction might be too slow without enzyme, making enzyme vital in living organism.

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What is the temperature of 0.750 mol of a gas stored in a 6,850 mL cylinder at 2.21 atm? A: 2.95 K

harina [27]

Option D: 246 K

According to ideal gas law:

$PV=nRT$ ...... (1)

Here, P is pressure, V is volume, n is number of moles, R is Universal gas constant and T is temperature of the gas. The value of R is $0.082 atm L K^{-1}mol^{-1}$ .

Number of moles of gas are 0.750 mol, volume of cylinder is 6850 mL and pressure of gas is 2.21 atm.

First converting volume from mL to L

$1 mL=10^{-3}L$

Thus,

6850 mL=6.850 L

Putting the values in equation (1),

$(2.21 atm)(6.850 L)=(0.750 mol)(0.082 atm L K^{-1}mol^{-1}T$

Rearranging

$T=\frac{(2.21 atm)(6.850 L)}{(0.750 mol)(0.082 atm L K^{-1}mol^{-1})}=246 K$ ,

Therefore, temperature of the gas is 246 K.

8 0

3 years ago

Read 2 more answers

1) Which of the following is the smallest unit of a chemio Tallest unit of a chemical element?

solong [7]

Answer:

Nanomachines will work with atoms, not nuclei. The smallest unit of a chemical element, about a third of a nanometer in diameter. Atoms make up molecules and solid objects.

Explanation:

6 0

3 years ago

The zero order reaction 2N2O→2N2+O2 has the reaction constant k is 6.28×10−3 molL s. If the initial concentration of N2O is 0.96

Talja [164]

Answer: The concentration of $N_2O$ in three significant figures will be 0.899 mol/L.

Explanation:

For the given reaction:

$2N_2O\rightarrow 2N_2+O_2$

The above reaction follows zero order kinetics. The rate law equation for zero order follows:

$k=\frac{1}{t}([A_o]-[A])$

where,

k = rate constant for the reaction = $6.28\times 10^{-3}\text{ mol }L^{-1}s^{-1}$

t = time taken = 10 sec

$[A_o]$ = initial concentration of the reactant = 0.962 mol/L

[A] = concentration of reactant after some time = ?

Putting values in above equation, we get:

$6.28\times 10^{-3}=\frac{1}{10}(0.962-[A])$

$[A]=0.899mol/L$

Hence, the concentration of $N_2O$ in three significant figures will be 0.899 mol/L.

5 0

3 years ago

3.15.8 cm3 of H2SO4 completely neutralised 20 cm3 of NaOH. The NaOH was 1.5 mol/dm3.

Furkat [3]

Answer:

Molarity = 0.95 mol/dm³

Explanation:

Given data:

Volume of H₂SO₄ = 15.8 cm³

Volume of NaOH = 20 cm³

Concentration of NaOH = 1.5 mol/dm³

Concentration of H₂SO₄ = ?

Solution:

Chemical equation:

NaOH + H₂SO₄ → Na₂SO₄ + H₂O

First of all we will calculate the number of moles of NaOH and for that we will convert the units first,

Volume = 20 cm³/1000 = 0.02 L

Concentration of NaOH = 1.5 mol/dm³

1 mol/dm³ = 1 mol/L

Concentration of NaOH = 1.5 mol/L

Number of moles of NaOH:

Molarity = number of moles / volume in L

1.5 M = number of moles / 0.02 L

Number of moles = 1.5 M ×0.02 L

Number of moles = 0.03 mol

Now we will compare the moles of NaOH and H₂SO₄

NaOH : H₂SO₄

2 : 1

0.03 : 1/2×0.03 = 0.015 mol

Concentration of H₂SO₄:

Volume of H₂SO₄:

15.8 cm³/1000 = 0.0158 L

Molarity = number of moles / volume in L

Molarity = 0.015 mol / 0.0158 L

Molarity = 0.95 mol/L

1 mol/L = 1 mol/dm³

Molarity = 0.95 mol/dm³

6 0

3 years ago

4) In a chemical change a _____________ substance forms.

Law Incorporation [45]

A complex substance forms when a chemical change takes place

8 0

3 years ago

Read 2 more answers