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Andru [333]
3 years ago
12

What substance takes part in an enzymatic reaction, but is unchanged by the reaction?

Chemistry
1 answer:
Ierofanga [76]3 years ago
5 0
The answer to this question would be: enzyme 

<span>Enzyme is a kind of catalyst that </span>will take part in the chemical reaction but it won't be reacted. E<span>nzyme </span>only helps by reducing the energy needed to start the reaction.
Theoretically, the enzyme is not mandatory needed but if you have an enzyme the reaction will be easier, thus increasing reaction speed. But in most case, the reaction might be too slow without enzyme, making enzyme vital in living organism.
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When rubbed against a silk cloth, a glass rod loses electrons. How does this affect the charges of the glass rod and the silk cl
AURORKA [14]

Answer:

Explanation:

The glass rod losses electrons because the silk cloth has a positive charge so it attracts the negative charge of the glass rod.

7 0
3 years ago
(a) Calculate the pH of a buffer that is 0.12 M in lactic acid and 0.11 M in sodium lactate. (b) Calculate the pH of a buffer fo
zepelin [54]

Answer:

fe9ufeohdwbkdwsdjvdwihdwkbfw

8 0
3 years ago
Which statement explains why carbon dioxide (CO2) is a gas at room temperature? A. There are constant interactions between the C
Nezavi [6.7K]

Answer:

B) There are weak interactions between the CO2 molecules.

Explanation:

Carbon dioxide is composed of one carbon atom that is structured between two atoms of oxygen, they are bonded with double bond and the CO2 is symmetrical because of the arrangement of the bond between them.It is less electronegative than Oxgen, this gives Oxgen the ability to attract the electron to themselves, and there is no intermolecular existing within carbon dioxide other bands waal forces.Compounds that are gases under the condition of room temperatures, and pressure usually have have small molecules. and their molecules is usually have van der Waals forces acting between them and theses forces are weak.This allows carbon dioxide molecules to be able to move freely as a gas.

6 0
4 years ago
A) Calculate the standard free-energy change at 25 ∘C for the following reaction:
Genrish500 [490]

Answer:

A) ΔG° = -3,80x10⁵ kJ

B) E° = 2,85V

Explanation:

A) It is possible to answer this problem using the standard ΔG's of formation. For the reaction:

Mg(s) + Fe²⁺(aq) → Mg²⁺(aq) + Fe(s)

The ΔG° of reaction is:

ΔG° = ΔGFe(s) + ΔGMg²⁺(aq) - (ΔGFe²⁺(aq) + ΔGMg(s) <em>(1)</em>

Where:

ΔGFe(s): 0kJ

ΔGMg²⁺(aq): -458,8 kJ

ΔGFe²⁺(aq): -78,9 kJ

ΔGMg(s): 0kJ

Replacing in (1):

ΔG° = 0kJ -458,8kJ - (-78,9kJ + okJ)

<em>ΔG° = -3,80x10² kJ ≡ -3,80x10⁵ kJ</em>

B) For the reaction:

X(s) + 2Y⁺(aq) → X²⁺(aq) + 2Y(s)

ΔG° = ΔH° - (T×ΔS°)

ΔG° = -629000J  - (298,15K×-263J/K)

ΔG° = -550587J

As ΔG° = - n×F×E⁰

Where n are electrons involved in the reaction (<em>2mol</em>), F is faraday constant (<em>96485 J/Vmol</em>) And E° is the standard cell potential

Replacing:

-550587J = - 2mol×96485J/Vmol×E⁰

<em>E° = 2,85V</em>

I hope it helps!

3 0
3 years ago
Consider the reaction: Mg(OH)₂ (s) ⇌ Mg²⁺ (aq) + 2 OH⁻ (aq)
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I’m a monkey and so are you I will shove my pp in you
6 0
4 years ago
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