You should never touch the subscripts, as that will change the composition. Hope I helped!
Answer:
Ok:
Explanation:
So grams = mols*MolarMass. Here, MolarMass (MM) = 105.99g which can be found using the periodic table. mols is given to be 0.802. We can then plug in to get that it corresponds to 85.0g.
Answer:
![m=59.3gCO_2](https://tex.z-dn.net/?f=m%3D59.3gCO_2)
Explanation:
Hello,
In this case, the first step is to compute the molar mass of carbon dioxide as shown below, considering it has one carbon atom and two oxygen atoms:
![M=12.011g/mol+2*15.999g/mol\\\\M=44.009g/mol](https://tex.z-dn.net/?f=M%3D12.011g%2Fmol%2B2%2A15.999g%2Fmol%5C%5C%5C%5CM%3D44.009g%2Fmol)
It is important to notice it is the mass in one mole of such compound. Afterwards, we need to use the Avogadro's number to compute the how many moles are in the given molecules of carbon dioxide as shown below:
![mol=8.12x10^{23}molec*\frac{1mol}{6.022x10^{23}molec} =1.35mol](https://tex.z-dn.net/?f=mol%3D8.12x10%5E%7B23%7Dmolec%2A%5Cfrac%7B1mol%7D%7B6.022x10%5E%7B23%7Dmolec%7D%20%3D1.35mol)
Finally, the mass by using the molar mass:
![m=1.35mol*\frac{44.009g}{1mol} \\\\m=59.3gCO_2](https://tex.z-dn.net/?f=m%3D1.35mol%2A%5Cfrac%7B44.009g%7D%7B1mol%7D%20%5C%5C%5C%5Cm%3D59.3gCO_2)
Best regards.
Answer:
The energy of a vibrating molecule is quantized much like the energy of an electron in the hydrogen atom. The energy levels of a vibrating molecule are given by the equation: En=(n+21)hv where n is a quantum number with possible values of 1, 2, ... and v is the frequency of vibration.
Explanation:
hope it helps.
have a wonderful day!
Answer:
blurred an pic mo paki ayos