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Flura [38]
3 years ago
5

In the haber process, ammonia is synthesized from nitrogen and hydrogen: n2 (g) + 3h2 (g) → 2nh3 (g) δg° at 298 k for this react

ion is -33.3 kj/mol. the value of δg at 298 k for a reaction mixture that consists of 1.9 atm n2, 1.6 atm h2, and 0.65 atm nh3 is __________. a -40.5 b -1.8 c -3.86 ´ 103 d -104.5 e -7.25 ´ 103
Chemistry
1 answer:
allsm [11]3 years ago
3 0

Answer:

e- 7.25 x 10³.

Explanation:

∵ ΔG = -RTlnK,

where, ΔG is the free energy change.

R is the general gas constant (R = 8.324 J/mol.K).

K is the equilibrium constant of the reaction.

  • For the reaction: <em>N₂(g) + 3H₂(g) → 2NH₃(g),</em>

K = (PNH₃)²/(PN₂)(PH₂)³ = (0.65)²/(1.9)(1.6)³ = 5.43 x 10⁻².

∵ ΔG = -RTlnK.

∴ ΔG = -(8.314 J/mol.K)(298 K) ln(5.43 x 10⁻²) = 7.218 x 10³ J/mol.

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In a solution with a pH of 3.0, the color of
Alinara [238K]

Answer:

A) litmus is red

Explanation:

To answer this question, it can be helpful to have the color charts. Litmus, phenolphthalein and methyl orange are ways to test the pH of a substance.

<u>Litmus paper</u>

Litmus can tell you if a substance is an acid or a base. You need to put the substance on both red litmus and blue litmus paper.

pH < 7: both papers are red. 3.0 is less than 7.

pH = 7: none of them change color

pH > 7: both papers are blue

<u>Phenolphthalein</u>

When this indicator is added to a substance, the result is either colorless or pink.

0 < pH ≤ 7: colorless. The color is not red or blue for pH 3.0.

pH > 7: pink

<u>Methyl orange</u>

0 < pH < 4: red. The color is not yellow if the pH is 3.0.

4 ≤ pH < 5: orange

pH ≥ 5: yellow

5 0
3 years ago
How many grams of helium must be released to reduce the pressure to 65 atmatm assuming ideal gas behavior? Express the answer in
lyudmila [28]

The question is incomplete, here is the complete question:

How many grams of helium must be released to reduce the pressure to 65 atm assuming ideal gas behavior. Note : 334-mL cylinder for use in chemistry lectures contains 5.209 g of helium at 23°C.

<u>Answer:</u> The mass of helium released is 1.6 grams

<u>Explanation:</u>

We are given:

Mass of helium in the cylinder = 5.209 g

To calculate the number of moles, we use the equation given by ideal gas equation:

PV = nRT

Or,

PV=\frac{w}{M}RT

where,

P = Pressure of the gas  = 65 atm

V = Volume of the gas  = 334 mL = 0.334 L   (Conversion factor: 1 L = 1000 mL)

w = Weight of the gas = ?

M = Molar mass of helium gas  = 4 g/mol

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = Temperature of the gas = 23^oC=[23+273]K=296K

Putting values in above equation, we get:

65atm\times 0.334L=\frac{w}{4g/mol}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 296K\\\\w=\frac{65\times 0.334\times 4}{0.0821\times 296}=3.573g

Mass of helium released = (5.209 - 3.573) g = 1.636 g = 1.6 g

Hence, the mass of helium released is 1.6 grams

5 0
3 years ago
While out on a hike, you find an unknown mineral. How would you test the mineral to find out what it is?
notsponge [240]
Are there answer choices or is it just right it your self?
6 0
3 years ago
What are the products formed when a base reacts with an acid?
brilliants [131]
It would become a salt 
5 0
3 years ago
How many grams of sodium chloride are required to prepare 500.0 ml of a 0.100 m solution?
scoray [572]

Answer:

  • <u>2.92 g</u>

Explanation:

<u>1) Data:</u>

a) V = 500.0 ml = 0.500 liter

b) M = 0.100

c) mass = ?

<u>2) Formulae:</u>

a) Molarity: M = n / V

b) Number of moles: n = mass in grams / molar mass

<u>3) Solution</u>

a) M = n / V ⇒ n = M × V = 0.1000 M × 0.500 liter = 0.0500 mol

b) molar mass NaCl = 58.443 g/mol

c) mass = n × molar mass = 0.0500 mol × 58.443 g/mol = 2.92 g

Answer: 2.92 g

4 0
3 years ago
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