Answer: In particular, let’s focus our attention on the behavior of each graph at and around . 2 and x= -1 for x < 2. There are open circles at both endpoints (2, 1) and (-2, 1). The third is h (x) = 1 / (x-2)^2, in which the function curves asymptotically towards y=0 and x=2 in quadrants one and two."
Step-by-step explanation: I think this is the problem ur on
The answer is B.13.
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Answer:
0
Step-by-step explanation:
∫ sin²(x) cos(x) dx
If u = sin(x), then du = cos(x) dx.
∫ u² du
⅓ u³ + C
⅓ sin³(x) + C
Evaluate between x=0 and x=π.
⅓ sin³(π) − ⅓ sin³(0)
0
A=10, B=11, C=12, etc.
Now, the "only" thing that remains to do is solving the above equation.
While making this problem I only made sure it has a solution. I didn't try to solve it myself and I didn't know it will end up with such "convoluted" polynomial. Sorry to everyone who tried to solve it... m(_ _)m
I think the best way to approach it is using the rational root theorem since we know that 
. Moreover we can deduce that 
since there is 
and 
.
After you succesfully solve it, you should get the answer 
.
Answer:
each triangle should weigh 2.5!
Step-by-step explanation:
each sides are equal. the side with only squares weighs 25. the squares on the opposite side weigh 10. 25-10 is equal to 15. there are 6 triangles. 15 divided by six gets you 2.5
