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Fittoniya [83]
3 years ago
5

18 points Which identifies an oxidation-reduction reaction?

Chemistry
2 answers:
OLEGan [10]3 years ago
5 0
A reaction in which oxidation numbers change
AlexFokin [52]3 years ago
3 0

Answer:

a reaction in which oxidation numbers change

Explanation:

here you go happy to help

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A container has a volume of 2.79 L and a pressure of 5.97 atm. If the pressure changes to 1460 mm Hg, what is the container’s ne
maw [93]

Answer:

8.68 L is the new volume

Explanation:

You use Boyle's law for this.

P_{1}V_{1}=P_{2}V_{2}

P_{1} = first pressure

P_{2} = second pressure

V_{1} = first volume

V_{2} = second volume

Convert pressure from atm to mmHg (use same units):

5.97 x 760 = 4537.2 -> 4.54 x 10³

...maintain 3 significant figures in calculation, and round as needed...

(4.54 x 10³ mmHg)(2.79 L) = (1460 mmHg)(V_{2})

(4.54 x 10³ mmHg)(2.79 L) / (1460 mmHg) = V_{2} = 8.68 L

Hope this helps :)

5 0
3 years ago
Formula of a copper (II)sulfate hydrate lab
s344n2d4d5 [400]

Answer:

Weigh the empty crucible, and then weigh into it between 2 g and 3 g of hydrated copper(II) sulphate. Record all weighings accurate to the nearest 0.01 g.

Support the crucible securely in the pipe-clay triangle on the tripod over the Bunsen burner.

Heat the crucible and contents, gently at first, over a medium Bunsen flame, so that the water of crystallisation is driven off steadily. The blue colour of the hydrated compound should gradually fade to the greyish-white of anhydrous copper(II) sulfate. Avoid over-heating, which may cause further decomposition, and stop heating immediately if the colour starts to blacken. If over-heated, toxic or corrosive fumes may be evolved. A total heating time of about 10 minutes should be enough.

Allow the crucible and contents to cool. The tongs may be used to move the hot crucible from the hot pipe-clay triangle onto the heat resistant mat where it should cool more rapidly.

Re-weigh the crucible and contents once cold.

Calculation:

Calculate the molar masses of H2O and CuSO4 (Relative atomic masses: H=1, O=16, S=32, Cu=64)

Calculate the mass of water driven off, and the mass of anhydrous copper(II) sulfate formed in your experiment

Calculate the number of moles of anhydrous copper(II) sulfate formed

Calculate the number of moles of water driven off

Calculate how many moles of water would have been driven off if 1 mole of anhydrous copper(II) sulfate had been formed

Write down the formula for hydrated copper(II) sulfate.

#*#*SHOW FULLSCREEN*#*#

Explanation:

7 0
3 years ago
What is the molecular formula of an empirical N2H3 if n=2? <br><br>SHOW WORK!
aliya0001 [1]

A compound's empirical formula tells you what the smallest whole number ratio between the atoms that make up that compound is.

I think of the empirical formula as a building block for molecules. A compound's molecular formula will depend on how many building blocks are needed to build a molecule of a given substance.

In your example, you know that the empirical formula of the compound is

NO

2

.

This tells you that the minimum ratio between nitrogen atoms and oxygen atoms is

1

:

2

. In other words, the molecular formula will be a multiple of this building block.

molecular formula

=

empirical formula

×

n

, where

n

- the number of building blocks needed to build the molecular formula.

You also know that the molar mass of your compound is

92 g/mol

.

This means that the molar mass of all the atoms that make up that molecule must add up to give

92 g/mol

.

So, how would you determine how many building blocks you need? Well, start by figuring out the molar mass of one building block, i.e. the molar mass of the empirical formula.

Since it contains one nitrogen atom and two oxygen atoms, you will get

1

×

14.0067 g/mol

+

2

×

15.9994 g/mol

=

46.0055 g/mol

So, if one building block has a molar mass of

46.0055 g/mol

, how many would you need to get the molecule?

46.0055 g/mol

⋅

n

=

92 g/mol

n

=

92

g/mol

46.0055

g/mol

=

1.99976

≈

2

This means that the compound's molecular formula, which lists all the atoms that make up a molecule, will be

(

NO

2

)

×

2

=

N

2

O

4

→

dinitrogen tetroxide

7 0
3 years ago
Read 2 more answers
Question 25———-A, YA are two isotopes of element A.
lakkis [162]

Answer:

Option C. 1

Explanation:

Step 1:

Determination of the Neutron of both isotopes. This is illustrated below.

For isotope y xA:

Mass number = y

Atomic number = x

Neutron =..?

Atomic number = proton number = x

Mass number = Proton + Neutron

y = x + Neutron

Rearrange

Neutron = y – x

For isotope (y + 1) xA:

Mass number = y + 1

Atomic number = x

Neutron =.?

Atomic number = proton number = x

Mass number = Proton + Neutron

y + 1 = x + Neutron

Rearrange

Neutron = y + 1 – x

Step 2:

Determination of the difference between the neutron number of both isotopes. This is illustrated below:

For isotope y xA:

Neutron number = y – x

For isotope (y + 1) xA:

Neutron number = y + 1 – x

Difference in neutron number

=> (y + 1 – x) – (y – x)

=> y + 1 – x – y + x

Rearrange

=> y – y + 1 – x + x

=> 1

Therefore, the difference in the neutron number of both isotopes is 1

6 0
3 years ago
If a person is throwing darts at a target, and shoots three in a row in the same spot on the 20 section outer ring, but none in
Gennadij [26K]
Maybe it is frisbee tag
5 0
3 years ago
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