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slega [8]
3 years ago
6

Natasha and Reanna observe a large airplane in the troposphere. Which experimental setup below would best determine how changing

wind speeds might affect the airplane’s flight time to its destination?
The airplane's flight time is the test variable (independent variable), the wind speed is the outcome variable (dependent variable), and the airplane is the constant.


The airplane's flight time is the outcome variable (dependent variable), the wind speed is the test variable (independent variable), and the airplane is the constant.


The airplane's flight time is the constant, the wind speed is the outcome variable (dependent variable), and the airplane is the test variable (independent variable).


The airplane's flight time is the test variable (independent variable), the airplane is the outcome variable (dependent variable), and the wind speed is the constant.
Chemistry
2 answers:
snow_lady [41]3 years ago
8 0

Answer:

i am pretty sure the answer is a

Explanation: because the airplane's flight time has to be the independent variable for it to affect the dependent variable that is the speed of how fast the airplane is going.

kykrilka [37]3 years ago
5 0

Answer:

i think its A but im not so sure but maybe some one else knows

Explanation:

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If 38g of sodium hydroxide reacts with 28g of carbon, how many grams of sodium carbonate are produced?
scZoUnD [109]

Answer:

Mass of sodium carbonate = 33.92 g

Explanation:

Given data:

Mass of sodium hydroxide = 38 g

Mass of carbon = 28 g

Mass of sodium carbonate produced = ?

Solution:

Chemical equation:

6NaOH + 2C → 2Na + 3H₂ + 2Na₂CO₃

Now will calculate the number of moles of reactants:

Number of moles of sodium hydroxide:

Number of moles = mass / molar mass

Number of moles = 38 g/ 40 g/mol

Number of moles = 0.95 mol

Number of moles of carbon:

Number of moles = mass / molar mass

Number of moles = 28 g/ 16 g/mol

Number of moles = 1.75 mol

Now we will compare the moles of both reactant with sodium carbonate.

                         C           :         Na₂CO₃

                         2           :           2

                       1.75         :         1.75

                  NaOH          :       Na₂CO₃      

                    6               :           2

                     0.95       :           2/6×0.95 = 0.32  

Number of moles of sodium carbonate produced by sodium hydroxide are less so it will limiting reactant.

Mass of sodium carbonate:

Mass = number of moles × molar mass

Mass = 0.32 mol × 106 g/mol

Mass = 33.92 g

5 0
3 years ago
Which of the following is true about science? (10 points)
Sedaia [141]
Economic concerns is the correct one
7 0
3 years ago
Question 8
castortr0y [4]

Answer:

The 5 chemical changes are. 1) Tarnish, 2) Rust, 3) Dissolve, 4) Burn, 5) Bake.

5 0
3 years ago
Which of the following has to remain constant to allow you to use the combined gas law for calculations?
Mazyrski [523]

Answer:

Amount of gas

Explanation:

The combined gas law has to do with pressure, volume, and temperature. All of them can be a variable that you have to solve for. However, amount of gas is not a variable you can solve for, which means it must remain constant.

4 0
3 years ago
The density of H2O2 is 1.407 g/mL, and the density of O2 is 1.428 g/L. How many liters of O2 can be made from 55 mL H2O2
balandron [24]

Explanation:

mass H2O2 = 55 mL(1.407 g/mL) = 80.85 g

molar mass H2O2 = 2(1.01 g/mol) + 2(16.00 g/mol) = 34.02 g/mol

moles H2O2 = 80.85 g/34.02 g/mol = 2.377 moles H2O2

For each mole of H2O2 you obtain 0.5 mole of O2 (see the equation).

moles O2 = 2.377 moles H2O2 (1 mole O2)/(2 moles H2O2) = 1.188 moles O2

Now, you need the temperature.  If you are at STP (273 K, and 1.00 atm) then 1 mole of an ideal gas at STP has a volume of 22.4 L.  Without temperature you are not really able to continue.  I will assume you are at STP.

Volume O2 = 1.188 moles O2(22.4 L/mole) = 0.0530 L of O2.

which is  53 mL.

8 0
2 years ago
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