Question

Calculate the percent yield of LiHCO3 if 58.0 g of CO2 produces 79.3 g of LiHCO3

Answer 1

On a Space shuttle, LiOH Is used to absorb CO2 to produce LiHCO3

LiOH + CO2 === LiHCO3

Now

58g of CO2 produces 79.3g of LiHCO3

This is the Actual Yield.

Recall

% Yield = Actual yield/Theoretical yield x100

NOW

We have to find the theoretical yield

From the equation of reaction

Now 58g of CO2 reacted

Converting to Moles

mole = Mass/Molar Mass

Molar mass of CO2=44g/mol

Mole = 58/44

=1.318moles of CO2

From the equation Of Reaction.

1 mole of CO2 reacts and Produces 1 mole of LiHCO3

Since their Mole ratio is 1:1

An Equal amount of LiHCO3 will be produced.

So 1.318moles of LiHCO3 will be produced.

Convert this mole to Mass

Mole =Mass/Molar Mass

Mass = Mole x Molar Mas

Molar Mass of LiHCO3 =68g/mol

Mass = 1.318 x 68

Mass = 89.62g.

This is the theoretical Yield.

% yield = 79.3/89.62 x 100

= 88.48%.