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Mariulka [41]
1 year ago
15

which bonds maintain the primary structure of a protein? question 7 options: ionic bonds hydrogen bonds peptide bonds disulfide

bonds\\
Chemistry
1 answer:
Mariulka [41]1 year ago
6 0

Proteins have four structures primary, secondary,m tertiary, and quaternary. The primary structure of the protein has been known to have peptide bonds. Thus, option C is correct.

<h3>What are peptide bonds?</h3>

Peptide bonds are the chemical bonds that are involved in protein polymer formation by linking the amino acid chains. They are also called amide bonds that are present between the nitrogen and the carbonyl atom.

The primary structure of the proteins includes the amino linked by the peptide bonds that make them look like linear structures. The secondary structures have hydrogen bonds and the tertiary have ionic and hydrophilic hydrogen bonds.

Therefore, option C. the primary structure of the protein contains peptide bonds.

Learn more about peptide bonds, here:

brainly.com/question/14902522

#SPJ4

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Which of the following is a correct inference that one can make about the burning of gasoline?
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It’s a physical change

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As you were climbing a a mountain, you noticed that rocks were crumbling below your feet and moving down the mountain. What two
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Weathering and erosion

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For an atom’s electrons, how many energy sublevels are present in the principal energy level n = 4?
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In this question given concerning the atom's electron, the number of energy sublevels present in the principal energy level n = 4 is to be determined. For this matter, it should be remembered that the number of sublevels of a certain principal energy level is equal to n. For this item, the number of sublevels is also 4. That is s, p, d and f.
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Bromine has two isotopes 79Br and 81Br, whose masses (78.9183 and 80.9163 amu) and abundances (50.69% and 49.31%, respectively)
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Answer:

Average atomic mass = 79.9034 amu

Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})

Given that:

<u>For first isotope: </u>

% = 50.69 %

Mass = 78.9183 amu

<u>For second isotope: </u>

% = 49.31 %

Mass = 80.9163 amu

Thus,  

Average\ atomic\ mass=\frac{50.69}{100}\times {78.9183}+\frac{49.31}{100}\times {80.9163}\ amu

Average\ atomic\ mass=40.0036+39.8998\ amu

<u>Average atomic mass = 79.9034 amu</u>

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3 years ago
What is the electron configuration of an element with atomic number 20?
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1s2,2s2.2p6,3s2,3p6,3d4,4s2
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