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IgorLugansk [536]
3 years ago
9

A chemist adds a sample of an ideal gas to a balloon and measures its volume. The chemist removes some of the gas from the ballo

on and measures its volume again. If the chemist removes 21% of the gas from the balloon, and the pressure and temperature of the gas do not change, what happens to the volume of the balloon?
Chemistry
1 answer:
meriva3 years ago
8 0

Answer:

The volume of the gas decreases also in a 21% based on the Avogadro's law

Explanation:

Based on Avogadro's law, the volume of a gas is directely proportional to the amount of moles of gas when temperature and pressure remain constants.

The formula is:

V1 / n1 = V2 / n2

<em>Where V is volume and n are moles in 1, initial state and 2, final state of the gas.</em>

<em />

At beginning, V1 = 100%, n1 = 100%,

As the chemist removes 21% of the gas, 79% of moles remain = n2.

Replacing:

100% / 100% = V2 / 79%

V2 = 79%, that means:

<h3>The volume of the gas decreases also in a 21% based on the Avogadro's law</h3>
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Answer:

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Explanation:

PH is a measure of how acidic or basic a liquid is. Specifically, from a dissolution. The acidity of a solution is essentially due to the concentration of hydrogen ions dissolved in it. In reality, the ions are not found alone, but are in the form of hydronium ions consisting of one oxygen molecule and three positively charged hydrogen. PH precisely measures this concentration. And to do it, we can use simple and very visual methods.

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3 years ago
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Sheena has a lump of sodium, a lump of potassium and a lump of lithium, but they’ve got mixed up and she doesn’t know which one
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Answer:

Explanation:

Just saw your request regarding answering this so here it is:

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What are the 2 products of photosynthesis
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Suppose you need to prepare 141.9 mL of a 0.223 M aqueous solution of NaCl. What mass of NaCl do you need to use to make the sol
Afina-wow [57]

Answer:

1.811 g

Explanation:

The computation of the mass need to use to make the solution is shown below:

We know that molarity is

Molarity = \frac{Number\ of\ moles}{Volume\ in\ L}

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Number\ of\ moles = Molarity\ \times Volume\ in\ L

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We simply applied the above formulas

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3 years ago
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