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IgorLugansk [536]
3 years ago
9

A chemist adds a sample of an ideal gas to a balloon and measures its volume. The chemist removes some of the gas from the ballo

on and measures its volume again. If the chemist removes 21% of the gas from the balloon, and the pressure and temperature of the gas do not change, what happens to the volume of the balloon?
Chemistry
1 answer:
meriva3 years ago
8 0

Answer:

The volume of the gas decreases also in a 21% based on the Avogadro's law

Explanation:

Based on Avogadro's law, the volume of a gas is directely proportional to the amount of moles of gas when temperature and pressure remain constants.

The formula is:

V1 / n1 = V2 / n2

<em>Where V is volume and n are moles in 1, initial state and 2, final state of the gas.</em>

<em />

At beginning, V1 = 100%, n1 = 100%,

As the chemist removes 21% of the gas, 79% of moles remain = n2.

Replacing:

100% / 100% = V2 / 79%

V2 = 79%, that means:

<h3>The volume of the gas decreases also in a 21% based on the Avogadro's law</h3>
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