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3 years ago

Solve the following 2 questions below, involving elements and reactions. *

Chemistry

2 answers:

Korvikt [17]3 years ago

7 0

*Make proportions to solve. Find the rate from the question 1.

Question 1 is 40.

There are 400 grams of NaCI. There are 10 drops.

Divide 400 by 10.

400 / 10 = 40

40 is the answer.

Now all we do is repeat the same process for question 2.

Question 2 is 20.

There are 800 grams of barium peroxide, and there are 40 drops.

Divide 800 by 40.

800 / 40 = 20

Answer = 20.

padilas [110]3 years ago

5 0

Answer:

1. 40 grams of NaCI

2. 20 grams of Barium Peroxide

Explanation:

<h3><u>In this question, we have to divide to find the amount of each element in a drop. </u></h3>

For Question 1, there are 400 grams of NaCI. There are 10 drops.

So, we have to divide 400 by 10.

400 / 10 = 40

We get 40 as our result, so 40 is the answer.

<h3><u>Same for this question, we use the process we did before.</u></h3>

There are 800 grams of barium peroxide, and there are 40 drops.

So, we divide 800 by 40.

800 / 40 = 20

We have the answer as 20.

Our final answers are going to be listed below:

Question 1 - 40
Question 2 - 20

Hope this helps you!

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Propane is often used to heat homes. The combustion of propane follows the following reaction: C3H8(g) + 5O2(g)  3CO2 (g) + 4H

swat32

Answer:

To release 7563 kJ of heat, we need to burn 163.17 grams of propane

Explanation:

<u>Step 1</u>: Data given

C3H8 + 5O2 -----------> 3CO2 + 4H2O ΔH° = –2044 kJ

This means every mole C3H8

Every mole of C3H8 produces 2044 kJ of heat when it burns (ΔH° is negative because it's an exothermic reaction)

<u>Step 2: </u>Calculate the number of moles to produce 7563 kJ of heat

1 mol = 2044 kJ

x mol = 7563 kJ

x = 7563/2044 = 3.70 moles

To produce 7563 kJ of heat we have to burn 3.70 moles of C3H8

<u>Step 3: </u>Calculate mass of propane

Mass propane = moles * Molar mass

Mass propane = 3.70 moles * 44.1 g/mol

Mass propane = 163.17 grams

To release 7563 kJ of heat, we need to burn 163.17 grams of propane

7 0

3 years ago

Characteristics of crystal

Orlov [11]

Answer:

Crystalline solids, or crystals, have distinctive internal structures that in turn lead to distinctive flat surfaces, or faces. The faces intersect at angles that are characteristic of the substance. When exposed to x-rays, each structure also produces a distinctive pattern that can be used to identify the material.

Explanation:

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3 years ago

What is commonly used to run a central heating system?

Troyanec [42]

Answer :- Electrical energy

Explanation :-
Geothermal energy is too large scale
solar energy is inefficient
Nuclear does more harm

7 0

3 years ago

A sample of a chromium-containing alloy weighing 3.450 g was dissolved in acid, and all the chromium in the sample was oxidized

Zina [86]

Answer:

H_2O + 2CrO_4^2- + 3SO_3^2- -> 3SO_3^2- + 2CrO_2^- + 2OH^-

Explanation:

Reduction half reaction

2H_2O + CrO_4^2- + 3e -> CrO_2^- + 4OH^-

Oxidation half reaction

2OH^- + SO_3^2- -> SO_4^2- + H_2O + 2e

Balanced overall equation

H_2O + 2CrO_4^2- + 3SO_3^2- -> 3SO_3^2- + 2CrO_2^- + 2OH^-

5 0

3 years ago

How much heat, in calories, is needed to raise the temperature of 125.0 g of Lead (c lead = 0.130 J/g°C) from 17.5°C to 41.1°C?

pav-90 [236]

95.6 cal
are needed.
Explanation:
Use the following equation:
q
=
m
c
Δ
T
,
where:
q
is heat energy,
m
is mass,
c
is specific heat capacity, and
Δ
T
is the change in temperature.
Δ
T
=
T
final
−
T
initial
Known
m
=
125 g
c
Pb
=
0.130
J
g
⋅
∘
C
T
initial
=
17.5
∘
C
T
final
=
42.1
∘
C
Δ
T
=
42.1
∘
C
−
17.5
∘
C
=
24.6
∘
C
Unknown
q
Solution
Plug the known values into the equation and solve.
q
=
(
125
g
)
×
(
0.130
J
g
⋅
∘
C
)
×
(
24.6
∘
C
)
=
400. J

(rounded to three significant figures)
Convert Joules to calories
1 J
=
0.2389 cal
to four significant figures.
400
.
J
×
0.2389
cal
1
J
=
95.6 cal

(rounded to three significant figures)
95.6 cal
are needed.

8 0

3 years ago