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3 years ago

Solve the following 2 questions below, involving elements and reactions. *

Chemistry

2 answers:

Korvikt [17]3 years ago

7 0

*Make proportions to solve. Find the rate from the question 1.

Question 1 is 40.

There are 400 grams of NaCI. There are 10 drops.

Divide 400 by 10.

400 / 10 = 40

40 is the answer.

Now all we do is repeat the same process for question 2.

Question 2 is 20.

There are 800 grams of barium peroxide, and there are 40 drops.

Divide 800 by 40.

800 / 40 = 20

Answer = 20.

padilas [110]3 years ago

5 0

Answer:

1. 40 grams of NaCI

2. 20 grams of Barium Peroxide

Explanation:

<h3><u>In this question, we have to divide to find the amount of each element in a drop. </u></h3>

For Question 1, there are 400 grams of NaCI. There are 10 drops.

So, we have to divide 400 by 10.

400 / 10 = 40

We get 40 as our result, so 40 is the answer.

<h3><u>Same for this question, we use the process we did before.</u></h3>

There are 800 grams of barium peroxide, and there are 40 drops.

So, we divide 800 by 40.

800 / 40 = 20

We have the answer as 20.

Our final answers are going to be listed below:

Question 1 - 40
Question 2 - 20

Hope this helps you!

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Decide whether the property measured was a chemical or physical property of X, if you can. If you don’t have enough information

olga nikolaevna [1]

Answer:

<u><em>See attachment for explanations.</em></u>

Explanation:

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1 year ago

Look at the four positions of Earth with respect to the sun. Florida is in the Northern hemisphere. At what position of Earth wi

Lena [83]

Answer:

2) Position 2 3

Explanation:

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3 years ago

How many moles are in 7.2x10^15 atoms of Pb?

fiasKO [112]

<h3>Answer:</h3>

1.2 × 10⁻⁸ mol Pb

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 7.2 × 10¹⁵ atoms Pb

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

[DA] Set up: $\displaystyle 7.2 \cdot 10^{15} \ atoms \ Pb(\frac{1 \ mol \ Pb}{6.022 \cdot 10^{23} \ atoms \ Pb})$
[DA] Multiply/Divide [Cancel out units]: $\displaystyle 1.19562 \cdot 10^{-8} \ mol \ Pb$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

1.19562 × 10⁻⁸ mol Pb ≈ 1.2 × 10⁻⁸ mol Pb

6 0

2 years ago

Nitrogen dioxide and water react to form nitric acid and nitrogen monoxide, like this:

posledela

Answer: The value of the equilibrium constant Kc for this reaction is 3.72

Explanation:

Equilibrium concentration of $HNO_3$ = $\frac{15.5g}{63g/mol\times 9.5L}=0.026M$

Equilibrium concentration of $NO$ = $\frac{16.6g}{30g/mol\times 9.5L}=0.058M$

Equilibrium concentration of $NO_2$ = $\frac{22.5g}{46g/mol\times 9.5L}=0.051M$

Equilibrium concentration of $H_2O$ = $\frac{189.0g}{18g/mol\times 9.5L}=1.10M$

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_c$

For the given chemical reaction:

$2HNO_3(aq)+NO(g)\rightarrow 3NO_2(g)+H_2O(l)$

The expression for $K_c$ is written as:

$K_c=\frac{[NO_2]^3\times [H_2O]^1}{[HNO_3]^2\times [NO]^1}$

$K_c=\frac{(0.051)^3\times (1.10)^1}{(0.026)^2\times (0.058)^1}$

$K_c=3.72$

Thus the value of the equilibrium constant Kc for this reaction is 3.72

5 0

2 years ago

In an ionic compound, the size of the ions affects the internuclear distance (the distance between the centers of adjacent ions)

jeyben [28]

Answer:

Li2S> Na2S> K2S> CsS

Explanation:

The lattice energy of ionic species depends on the relative sizes of ions in the ionic compounds. As the size of ions increases, the lattice energy decreases and vice versa.

When the size of the anions are the same, the lattice energy now depends on the relative sizes of the cations. Therefore, since all the compounds are sulphides and the order of magnitude of ionic sizes is: Li^+ < Na^+ < K^+ < Cs^+.

Therefore, the order of decrease in lattice energy is; Li2S> Na2S> K2S> CsS

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3 years ago