What volume of a 3.00M KL stock solution would you use to make 0.300 L of a 1.25M Kl solution?
1 answer:
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Answer:
<h3>The answer is 4.65 moles</h3>Explanation:
To find the number of moles given it's number of entities we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question
N = 2.8 × 10²⁴ atoms of Cl2
So we have
We have the final answer as
<h3>4.65 moles</h3>Hope this helps you