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2 years ago

At high temperatures, sulfur combines with iron to form brown-black iron(II) sulfide:

Chemistry

1 answer:

taurus [48]2 years ago

3 0

The percent yield : 79.9%

<h3>Further eplanation </h3>

Percent yield is the comparison of the amount of product obtained from a reaction with the amount you calculated

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients

Reaction

Fe(s)+S(s)⇒FeS(s)

The reaction produces 6.29 g of iron(II) sulfide⇒an actual yield

The maximum amount that can be produced is 7.87 g ⇒ A theoretical yield

$\tt \%yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{6.29}{7.87}\times 100\5=79.9\%$

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The process of pouring a mixture though a filter to catch the larger particles while allowing the smaller particles to pass thro

Annette [7]

This process is called filtration. This process is a solid-fluid separation by the use of a medium wherein only the fluid (gases or liquids) can go through it. The medium is called the filter while the fluid that passed through the filter is called the filtrate. The solid particles are the large particles which cannot pass through the filter.

4 0

3 years ago

How is molarity measured?

Tanzania [10]

The answer to this question will be C

6 0

2 years ago

A 5.00 L sample of air at 0 C is warmed to 100.0 C. What is the new volume of the air? First, identify V1.

Paladinen [302]

Answer : The new volume of the air is, 6.83 L

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=5.00L\\T_1=0^oC=(0+273)K=273K\\V_2=?\\T_2=100^oC=(100+273)K=373K$

Putting values in above equation, we get:

$\frac{5.00L}{273K}=\frac{V_2}{373K}\\\\V_2=6.83L$

Therefore, the new volume of the air is, 6.83 L

6 0

3 years ago

The freezing point of 42.19 g of a pure solvent is measured to be 43.17 ºC. When 2.03 g of an unknown solute (assume the van 't

vovikov84 [41]

Answer:

The molality of the solution is 0.3716 mol/kg

The number of moles of solute is 0.0157 mol

The molecular weight of the solute is 129.30 g/mol

The molar mass of the solute is 129.32 g/mol

Explanation:

m (molality of the solution) = ∆T/Kf = (43.17 - 40.32)/7.67 = 0.3716 mol/kg

Number of moles of solute = molality × mass of solvent in kilogram = 0.3716 × 0.04219 = 0.0157 mol

Molecular weight of solute = mass/number of moles = 2.03/0.0157 = 129.3 g/mol

When Kf = 7.66 °C.kg/mol

Molar mass = 2.03 ÷ (2.85/7.66 × 0.04219) = 129.32 g/mol

4 0

2 years ago

Which has more mass, a mole of water (h2o) or a mole of glucose (c6h12o6)?

Semenov [28]

It is important to note that mass and mole pertain to different units of measurement, thus, 1 mole of one substance may have a lower or higher mass compared to a different substance. The mass of an object gives a measure of the number of atoms present in the substance while the number of moles of a substance refers to the amount of a chemical substance it has and is often used for chemical reactions.

For this problem, we first get the molar mass of each substance:

Molar mass of H2O = 18.0153 g/mol
Molar mass of C6H12O6 = 180.1559 g/mol

We then convert each substance into units of mass (grams), where:

1 mol H20 x 18.0153 g/mol = 18.0153 g H20
1 mol C6H12O6 x 180.1559 g/mol = 180.1559 g C6H12O6

It was then determined that 1 mole of glucose has more mass than 1 mole of water.

3 0

3 years ago