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iVinArrow [24]
3 years ago
15

At high temperatures, sulfur combines with iron to form brown-black iron(II) sulfide:

Chemistry
1 answer:
taurus [48]3 years ago
3 0

The percent yield : 79.9%

<h3>Further eplanation </h3>

Percent yield is the comparison of the amount of product obtained from a reaction with the amount you calculated

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients

Reaction

Fe(s)+S(s)⇒FeS(s)

The reaction produces 6.29 g of iron(II) sulfide⇒an actual yield

The maximum  amount that can be produced is 7.87 g ⇒ A theoretical yield

\tt \%yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{6.29}{7.87}\times 100\5=79.9\%

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Answer: The activation energy Ea for this reaction is 22689.8 J/mol

Explanation:

According to Arrhenius equation with change in temperature, the formula is as follows.

ln \frac{k_{2}}{k_{1}} = \frac{-E_{a}}{R}[\frac{1}{T_{2}} - \frac{1}{T_{1}}]

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3 0
3 years ago
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