When we balance the given equation
NO₂Cl(g) ⇄ NO₂(g) + Cl₂(g)
We will get
2NO₂Cl(g) ⇄ 2NO₂(g) + Cl₂(g)
Solution:
Balancing the given equation
NO₂Cl(g) ⇄ NO₂(g) + Cl₂(g)
We have to balance the number of Cl
2NO₂Cl(g) ⇄ NO₂(g) + Cl₂(g)
We have to balance the number of N, O.
2NO₂Cl(g) ⇄ 2NO₂(g) + Cl₂(g)
We will get the balanced equation
2NO₂Cl(g) ⇄ 2NO₂(g) + Cl₂(g)
The reaction quotient will be
Qc = [product] / [reactant]
Qc = [NO₂(g) + Cl₂(g)] / [NO₂Cl(g)]
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A.) In the beginning the universe was too hot for atoms to exist.
Because choice b,c,and d are all part of the big bang theory.
Here we have to draw the four isomers of the compound 3-bromo-4-fluorohexane.
The four isomers of the compound is shown in the figure.
In an organic molecule the chiral -C center is that where four (4) different groups are present. In 3-bromo-4-fluorohexane the 3 and 4 positions are chiral centers. The possible isomers of a molecule can be obtained from the formula 2n. As here 2 chiral centers are present thus number of stereoisomers will be 2×2 = 4.
The four different isomers as shown in the figure are 3R-, 4R-; 3S-, 4S; 3R, 4S and 3S-, 4R- 3-bromo-4-fluorohexane.
In the 3-bromo-4-fluorohexane the functional groups are -Br, C₂H₅, -C₃H₆F and -H for 3-position and -F, -C₂H₅, -C₃H₆ and -H for 4-position respectively.
The priority of the -3 position will be Br > C₃H₆F > C₂H₅ > H and for -4 position F > C₃H₆Br > C₂H₅ > H. If the rotation from the higher priority group to lower is clockwise and anticlockwise then the S- and R- notation are used respectively. However if the -H atom is present at the horizontal position then the notation will be reverse.
Thus the four isomers of the compound is shown.
Answer:
I honestly dont know but its cool problably from water fill or from the waves going to much
Explanation:
Answer:
My lovely people the answer is SOLAR
Explanation:
i just know