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3 years ago

Why do solids maintain their shape, whereas fluids do not?

Chemistry

2 answers:

Wittaler [7]3 years ago

5 0

Answer: Option (d) is the correct answer.

Explanation:

In solids, the molecules are held more tightly due to the existence of strong intermolecular forces of attraction between its particles.

Hence, they have a definite shape and volume. So, these molecules are arranged in a regular pattern and they are able to vibrate at their position.

On the other hand in liquids, molecules are slightly away from each other as they are held by less strong intermolecular forces of attraction. Hence, liquids do not have a definite shape but they tend to occupy the shape of container in which they are placed.

Thus, we can conclude that solids maintain their shape, whereas fluids do not because the molecules in solids maintain a regular pattern and only vibrate, or move very slowly.

Vinvika [58]3 years ago

3 0

Solids maintain their shape, whereas fluids do not because <span>the molecules in solids maintain a regular pattern and only vibrate, or move very slowly. The correct option among all the options that are given in the question is the last option or option "d". I hope the answer has come to your help.</span>

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3 years ago

Calculate the molarity of a solution of Nach if it contains 7.2.g Nach in 100.0 mL of solution. andver: m Nach . .

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Answer:

1.23 M

Explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity

V = volume of solution in liter ,

n = moles of solute ,

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Hence ,

n = w / m

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m = molecular mass .

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w = given mass of NaCl = 7.2 g

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n = w / m = 7.2 g / 58.5 g/mol = 0.123 mol

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3 years ago

WILL MARK BRANILEST

ahrayia [7]

Answer:

FeCl3 is the limiting reactant

O2 is in excess

Theoretical yield Cl2 = 9.84 grams

The % yield is 96.5 %

Explanation:

Step 1: Data given

Mass of FeCl3 = 15.0 grams

Moles O2 = 4.0 moles

Mass of Cl2 produced = 9.5 grams

Step 2: The balanced equation

4FeCl3 + 3O2 → 2Fe2O3 + 6Cl2

Step 3: Calculate moles FeCl3

Moles FeCl3 = mass FeCl3 / molar mass FeCl3

Moles FeCl3 = 15.0 grams / 162.2 g/mol

Moles FeCl3 = 0.0925 moles

Step 4: Calculate limiting reactant

FeCl3 is the limiting reactant. Because we have way more (more than ratio 3:4) moles O2 than FeCl3. It will completely be consumed (0.0925 moles). O2 is in excess. There will react = 0.069375 moles O2

There will remain 4.0 - 0.069375 = 3.930625 moles

Step 5: Calculate moles Cl2

For 4 moles FeCl3 we need 3 moles O2 to produce 2 moles Fe2O3 and 6 moles Cl2

For 0.0925 moles FeCl3 moles we'll have 6/4 * 0.0925 = 0.13875 moles Cl2.

Step 6: Calculate mass Cl2

Mass Cl2 = moles * molar mass

Mass Cl2 = 0.13875 moles * 70.9 g/mol

Mass Cl2 = 9.84 grams

Step 7: Calculate % yield

% yield = (actual yield / theoretical yield) * 100%

% yield = (9.5 grams / 9.84 grams ) * 100%

% yield = 96.5 %

The % yield is 96.5 %

4 0

3 years ago