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zepelin [54]
3 years ago
6

HELP PLEASE THIS IS HARD-!

Mathematics
1 answer:
alexgriva [62]3 years ago
3 0

Answer:

12

Step-by-step explanation:

\frac{2(2)}{2} +2(2)+\frac{2(6)}{2} =2+4+6\\                                                     =12

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Grace received a bonus of 12% to her weekly wage. What was Grace's bonus if her weekly wage is $1850?
pickupchik [31]
1850 * 1.12 = 2072 <==

or this way...
1850 + 0.12(1850) = 1850 + 222 = 2072 <==
8 0
4 years ago
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Order operations <br> 3 + 11 - 3 x 17<br> please show your work
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3 x 17 = 54
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Suppose it is known that 60% of radio listeners at a particular college are smokers. A sample of 500 students from the college i
vladimir1956 [14]

Answer:

The probability that at least 280 of these students are smokers is 0.9664.

Step-by-step explanation:

Let the random variable <em>X</em> be defined as the number of students at a particular college who are smokers

The random variable <em>X</em> follows a Binomial distribution with parameters n = 500 and p = 0.60.

But the sample selected is too large and the probability of success is close to 0.50.

So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

1. np ≥ 10

2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=500\times 0.60=300>10\\n(1-p)=500\times(1-0.60)=200>10

Thus, a Normal approximation to binomial can be applied.

So,  

X\sim N(\mu=600, \sigma=\sqrt{120})

Compute the probability that at least 280 of these students are smokers as follows:

Apply continuity correction:

P (X ≥ 280) = P (X > 280 + 0.50)

                   = P (X > 280.50)

                   =P(\frac{X-\mu}{\sigma}>\frac{280-300}{\sqrt{120}}\\=P(Z>-1.83)\\=P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that at least 280 of these students are smokers is 0.9664.

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3 years ago
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Answer: 16 fl oz

Step-by-step explanation:

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aleksandrvk [35]

Answer:

D: 57 feet below sea level

7 0
3 years ago
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