An atom has 13 protons and 14 neutrons. what is its mass number?

When one atom of hydrogen (H) combines with one atom of chlorine (Cl), a polar covalent bond forms between the H and the more el

Daniel [21]

C. The valence electrons spend more time around the atom of Cl.

6 0

3 years ago

What would refract the most? air, water, or glass?

Setler [38]

Glass if my brain is straight from all of the monster energy

8 0

3 years ago

Read 2 more answers

How much heat is absorbed when a 298.3 g piece of brass goes from 30.0 to 150

igor_vitrenko [27]

Answer:

Q = 1360.248 j

Explanation:

Given data:

Mass of brass = 298.3 g

Initial temperature = 30.0°C

Final temperature = 150°C

Specific heat capacity of brass = 0.038 J/g.°C

Heat absorbed = ?

SOLUTION:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 150°C - 30.0°C

ΔT = 120°C

Q = 298.3 g × 0.038 J/g.°C × 120°C

Q = 1360.248 j

3 0

3 years ago

The specific heat of a metal is 3.76 cal/g°C. How much heat energy will it take to heat a 25.0 g cylinder of the metal from 21.5

Rudiy27

Answer:

The correct answer is "5217 Cal".

Explanation:

The given values are:

Specific heat,

c = 3.76 cal/g°C

Mass,

m = 25.0 g

Initial temperature,

T₁ = 21.5°C

Final temperature,

T₂ = 77.0°C

Now,

The heat energy will be:

⇒ $Q=mc \Delta t$

On substituting the given values, we get

⇒ $=25.0\times 3.76\times (77-21.5)$

⇒ $=25\times 3.76\times 55.5$

⇒ $=5217 \ Cal$

4 0

3 years ago

11mg of cyanide per kilogram of body weight is lethal for 50% of domestic chickens. How many grams per kilogram of body weight i

Nookie1986 [14]

Answer:

$0.033g$

Explanation:

Hello,

In this case, since 11 mg per kilogram of body weight has the given lethality, the mg that turn out lethal for a chicken weighting 3 kg is computed by using a rule of three:

$11mg\longrightarrow 1kg\\\\x\ \ \ \ \ \ \longrightarrow 3kg$

Thus, we obtain:

$x=\frac{3kg*11mg}{1kg}\\ \\x=33mg$

That in grams is:

$=33mg*\frac{1g}{1000mg} \\\\=0.033g$

Regards.

7 0

3 years ago