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JulsSmile [24]
3 years ago
5

The equation below shows the products formed when a solution of silver nitrate (AgNO3) reacts with a solution of sodium chloride

(NaCl).
AgNO3 + NaCl → NaNO3 + AgCl

(Reactants) → (Products)


In this equation, the total mass of the reactants is
A) equal to the mass of AgCl.
B) less than the mass of AgCl.
C) equal to the total mass of the products.
D) greater than the total mass of the products.
Chemistry
2 answers:
Alecsey [184]3 years ago
4 0
C<span>) <span>igual a la masa total de los productos. <span> equal to the total mass of the products.

</span></span></span>In this equation, the total mass of the reactants is <span>equal to the total mass of the products.</span> This is in accordance with the law of conservation of mass.
d1i1m1o1n [39]3 years ago
3 0
I would say that the answer has to be C
Since there is no change in mols on both sides of the equation the mass is constant
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A 0.80 L sample of gas has a temperature of 27°C and a pressure of 0.925 atm. How many moles of gas are present?
ololo11 [35]

Answer:

n= 0.03 moles

Explanation:

Using the ideal gas law:

PV=nRT

nRT=PV

n= PV/RT

 n: moles

 P: pressure in atm

 V= volume in L

 R= Avogadro's constant = 0.0821

 T= Temperature in K => ºC+273.15

n= (0.925 atm)(0.80 L) / (0.0821)(300.15 K)

n= 0.03 moles

6 0
3 years ago
Using henry's law, calculate the molar concentration of o2 in the surface water of a mountain lake saturated with air at 20 ∘c a
s2008m [1.1K]

Answer: The molar concentration of oxygen gas in water is 1.43\times 10^{-7} mol/L.

Explanation:

Partial pressure of the O_2gas = 685 torr = 0.8905 bar

1 torr = 0.0013 bar

According Henry's law:

p_{o_2}=K_H\times\chi_{O_2}

Value of Henry's constant of oxygen gas at 20 °C in water = 34860 bar

0.0013=34860 bar\times \chi_{O_2}

\chi_{O_2}=\frac{0.8905 bar}{34680 bar}=2.56\times 10^{-5}

Let the number of moles of O_2 gas in 1 liter water be n.

1 Liter water = 1000 g of water

Moles of water in 1 L n_w=\frac{1000 g}{18 g/mol}=55.55 mol

\chi_{O_2}=\frac{n}{n+n_w}

2.56\times 10^{-5}=\frac{n}{n+55.55}

n=1.43\times 10^{-7} moles

Molarity=\frac{\text{Moles of}O_2}{Volume}

Molar concentration of oxygen gas in 1 L of water:

=\frac{1.43\times 10^{-7} moles}{1 L}=1.43\times 10^{-7} mol/L

The molar concentration of oxygen gas in water is 1.43\times 10^{-7} mol/L.

4 0
3 years ago
An element with the general electron configuration for its outermost electrons of ns2np1 would be in which element group?
Firdavs [7]

Electron configuration is the electron distribution in the molecular and atomic orbital. An element with configuration ns²np¹ will be in the 3A group. Thus, option B is correct.

<h3>What is electronic configuration?</h3>

The electronic configuration has been the arrangement and distribution of the sub-atomic particle, an electron in the atomic shells.

The electronic configuration given is, ns²np¹. Here, there are three valence electrons in the outermost orbit. As it has been known that the number of the valence electron gives the number of the group.

Therefore, option B. 3A group or 13 group is the correct option.

Learn more about electronic configuration here:

brainly.com/question/11182760

#SPJ4

Your question is incomplete, but most probably your full question was, An element with the general electron configuration for its outermost electrons of ns2np1 would be in which group?

a. 2a

b. 3a

c. 4a

d. 5a

e. 8a

8 0
2 years ago
Why does the reaction proceed more quickly when the surface area is increased?
Gelneren [198K]
When particles collide with the surface of the solid.
3 0
2 years ago
In the Reaction CuCl2 + 2 NaNO3 —&gt; Cu(NO3)2 + 2 Naci
Lunna [17]

Explanation:

The molar mass of the compounds are incorrect

5 0
2 years ago
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