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JulsSmile [24]
3 years ago
5

The equation below shows the products formed when a solution of silver nitrate (AgNO3) reacts with a solution of sodium chloride

(NaCl).
AgNO3 + NaCl → NaNO3 + AgCl

(Reactants) → (Products)


In this equation, the total mass of the reactants is
A) equal to the mass of AgCl.
B) less than the mass of AgCl.
C) equal to the total mass of the products.
D) greater than the total mass of the products.
Chemistry
2 answers:
Alecsey [184]3 years ago
4 0
C<span>) <span>igual a la masa total de los productos. <span> equal to the total mass of the products.

</span></span></span>In this equation, the total mass of the reactants is <span>equal to the total mass of the products.</span> This is in accordance with the law of conservation of mass.
d1i1m1o1n [39]3 years ago
3 0
I would say that the answer has to be C
Since there is no change in mols on both sides of the equation the mass is constant
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If there were an element above fluorine in the periodic table what phase would you expect it to be in (at room temp)?
AysviL [449]

If there were an element above fluorine, its state would be a gas. This is because fluorine is located in the non-metal section of the periodic table which can all be found as a gas at room temperature.

3 0
3 years ago
rank the four gases (air, exhaled air, gas produced from the decomposition of H2O2, gas from decomposition of NaHCO3, in order o
SVEN [57.7K]

Answer: H₂O₂ (94%) > Air (23%) > Exhaled air (13%) > NaHCO₃ (0%)


Initial important note:


Although NaHCO₃ contents oxygen atoms, and you can calculate its compositoin, the resulting gas does not containg pure oxygen gas (O₂). For the comparisson it is not useful to calculate the content of oxygent atoms, but the concentration of O₂ gas. As such, the gas from NaHCO₃ contains 0% of pure O₂, that is why it is ranked last.


1) Air:


Source: internet


Approximate 23%. It is variable, because air is not a pure substance but a mixture of gases, whose compositon is not unique.


2) Exhaled air:


Source: internet.


Approximate 13%. The compositon of the air changes in our lungs, due to the respiration process: we inhale fresh air with around 23% of oxygen, part of this oxygen pass to the cells (lungs - blood - heart - cells) and then it is exhaled with a lower content of air and a greater content of CO₂


3) Air from the decomposition of H₂O₂.


In this case we can do a chemical calculation, since we can state the chemical equation of the reaction:


i) Chemical Equation:


H₂O₂ (g) → H₂ (g) + O₂ (g)


ii) mole ratio of the products 1 mol H₂ : 1 mol O₂


iii) convert moles into mass (grams)


1 mol H₂ × 2 × 1.008 g/mol = 2.016 g


1 mol O₂ × 2 × 15.999 g/mol = 31.998 g


Composition, % = [31.998 g / (2.016 g + 31.998 g) ] × 100 ≈ 94%



4) Air from the decomposition of NaHCO₃:


i) chemical equation:


2 NaHCO₃(s) → Na₂CO₃(s) + CO₂(g) + H₂O(g)


ii) mole ratio: take into account only the gases in the products:


1 mol CO₂ (g) : 1 mol H₂O


iii) mass in grams


CO₂: molar mass ia approximately 44.01 g/mol


H₂O: molar mass is approximately 18.02 g/mol


iii) Those gases although have oxygen atoms, do not hae free oxygen gas, which is what we are compariing. That means, that from the decomposition of NaHCO₃ you get 0% oxygen gas.


5) The result is:


H₂O₂ (94%) > Air (23%) > Exhaled air (13%) > NaHCO₃ (0%)

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3 years ago
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How do you make a model of something you cannot see?
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You have to imagine it
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A 41.1 g sample of solid CO2 (dry ice) is added to a container at a temperature of 100 K with a volume of 3.4 L. If the containe
Morgarella [4.7K]

Answer:

The pressure inside the container is 6.7 atm

Explanation:

We have the ideal gas equation: P x V = n x R x T

whereas, P (pressure, atm), V (volume, L), n (mole, mol), R (ideal gas constant, 0.082), T (temperature, Kelvin)

Since the container is evacuated and then sealed, the volume of the body of gas is the volume of the container.

So we can calculate the pressure by

P = n x R x T / V

where as,

n = 41.1 g / 44 g/mol = 0.934 mol

Hence P = 0.934 x 0.082 x 298 / 3.4 L = 6.7 atm

3 0
3 years ago
Which location represents a period on a Periodic Table?   A. a vertical row   B. a horizontal row   C. a diagonal row on the per
prohojiy [21]
The periods inside the Periodic Table is B. a horizontal row, and is numbered 1 through 7


hope this helps
7 0
3 years ago
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