B, the Internet.
If Caitlin told Teddy that the largest diamond was found YESTERDAY then it wouldn't be in last month's science magazine. It also wouldn't be able to be in an encyclopedia at the library because there wouldn't have been any time to write, publish, and for the library to get the encyclopedia in one day. Caitlin's parents may not know about Caitlin's claim or about the diamond in the first place. The Internet would likely have an article about the news-breaking diamond as soon as possible.
Explanation:
b. What useful functions do oxidation numbers serve?
It is used to show oxidation and reduction (loss and gain of electrons)
b. How many molecules are in 1 mole of molecules?
1 mole = 6.022 * 10^23 molecules
c. What is the name given to the number of molecules in 1 mole?
Avogadro's Number of molecules
21. a. What is the molar mass of an element?
This is the mass of an element divided by the number of moles.
Molar mass = Mass / Number of moles
b. Write the molar mass rounded to two decimal places of carbon, neon, iron and uranium.
amu = Atomic Mass Unit
Carbon = 12.01 amu
Neon = 20.18 amu
Iron = 55.85 amu
Uranium = 238.03 amu
A buffer is a solution that can resist pH change upon the addition of an acidic or basic components. It is able to neutralize small amounts of added acid or base, thus maintaining the pH of the solution relatively stable. This is important for processes and/or reactions which require specific and stable pH ranges. Buffer solutions have a working pH range and capacity which dictate how much acid/base can be neutralized before pH changes, and the amount by which it will change.
The mass of lime that can be produced from 4.510 Kg of limestone is calculated as below
calculate the moles of CaCO3 used
that is moles =mass/molar mass
convert Kg to g = 4.510 x1000 =4510g
= 4510 / 100 =45.10 moles
CaCO3 = CaO +O2
by use of mole ratio between CaCO3 to CaO (1:1) the moles of CaO is also= 45.10 moles
mass of CaO = moles x molar mass
45.10 x56 = 2525.6 g of CaO
Answer:
0.67mol/Kg
Explanation:
The following were obtained from the question:
Mole of solute = 0.50mol
Mass of solvent = 750g = 750/1000 = 0.75Kg
Molality =?
Molality = mole of solute /mass of solvent
Molality = 0.5/0.75
Molality = 0.67mol/Kg
