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grandymaker [24]
3 years ago
5

A solution is made by dissolving 4.0 moles of sodium chloride (NaCl) in 2.05 kilograms of water. If the molal boiling point cons

tant for water (Kb) is 0.51 °C/m, what would be the boiling point of this solution? Show all of the work needed to solve this problem.
Chemistry
1 answer:
kozerog [31]3 years ago
4 0
Properties of a solution that depend only on the ratio of the number of particles of solute and solvent in the solution are known as colligative properties. For this problem, we use boiling point elevation concept.

ΔT(boiling point)  = (Kb)mi
ΔT(boiling point)  = (0.51 C-kg / mol )(4.0 mol / 2.05 kg ) (2)
ΔT(boiling point)  = 1.99 C

T(boiling point) = 101.99 C
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5.09

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Tin (II) fluoride, formerly found in many kinds of toothpaste, is formed in this reaction: Sn (s) + 2HF (g) ——&gt; SnF2 (s) + H2
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1.34 L of HF

Explanation:

We have the following chemical reaction:

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First we calculate the number of moles of SnF₂:

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number of moles of SnF₂ = 5 / 157 = 0.03 moles

From the chemical reaction we see that 1 mole of SnF₂ are produced from 2 moles of SnF₂. This will mean that 0.03 moles of SnF₂ are produced from 0.06 moles of HF.

Now at standard temperature and pressure (STP) we can use the following formula to calculate the volume of HF:

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brainly.com/question/8857334

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8 0
3 years ago
A gas occupies a volume of 31.0 ml at 19.0°C. If the gas temperature rises to 38.0°C at constant pressure. Calculate the new vol
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The correct answer is 0.0033 L (33.0 mL)

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We have the following data:

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We calculate V₂ from the mathematical expression, as follows:

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