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Arlecino [84]
2 years ago
7

Explain the difference between objects that are sources of light and objects that reflect light

Physics
1 answer:
podryga [215]2 years ago
4 0

Answer:

sun is the main source while the other object reflect light on the sun

Explanation:

nasa libro yans

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A swimmer bounces straight up from a diving board and falls feet first into a pool. She starts with a velocity of 4.00 m/s, and
Svetlanka [38]

Answer:

a = 1.152s

b = 0.817 m

c = 7.29m/s

Explanation: let the following

From the first equation of linear motion

V = u+at..........1

parameters be represented as :

t = Time taken

v = Final velocity

a = Acceleration due to gravity = 9.8m/s²

u = Initial velocity = 4 m/s

s = Displacement

V = 0

Substitute the values into equation 1

0 = 4-9.8(t)

-4 = -9.8t

t = 4/9.8

t = 0.408s

From : s = ut+1/2at^2.........2

S = 4×0.408+0.5(-9.8)×0.408^2

S= 1.632-4.9(0.166)

S = 1.632-0.815

S = 0.817m

Her highest height above the board is 0.817 m

Total height she would fall is 0.817+1.90 = 2.717 m

From equation 2

s = ut+1/2at^2

2.717 m = 0t+0.5(9.8)t^2

2.717 m = 0+4.9t^2

2.717 m = 4.9t^2

2.717/4.9 = t^2

0.554 =t^2

t =√0.554

t = 0.744s

Hence, her feet were in the air for 0.744+0.408seconds

= 1.152s

Also recall from equation 1

V= u+at

V = 0+9.8(0.744)

V = 7.29m/s

Hence, the velocity when she hits the water is 7.29m/s

Finally,

a = 1.152s

b = 0.817 m

c = 7.29m/s

4 0
2 years ago
A bungee jumper launches herself off a bridge, how would you describe her motion?
Blizzard [7]
It would depend on how she jumped off but based on it sounds it would be a curving motion
4 0
3 years ago
Read 2 more answers
A Subtle Relationship
liraira [26]

Answer:

i really wish i can help

Explanation:

but we are not all einsteins

6 0
1 year ago
NaAlSi3O8 number of atoms persent​
ad-work [718]

Answer is in the photo. I can only upload it to a file hosting service. link below!

tinyurl.com/wpazsebu

5 0
2 years ago
What is the minimum speed needed to fire a champagne cork a distance of 11m?
Crank

To start with solving this problem, let us assume a launch angle of 45 degrees since that gives out the maximum range for given initial speed. Also assuming that it was launched at ground level since no initial height was given. Using g = 9.8 m/s^2, the initial velocity is calculated using the formula:

(v sinθ)^2 = (v0 sinθ)^2 – 2 g d

where v is final velocity = 0 at the peak, v0 is the initial velocity, d is distance = 11 m

Rearranging to find for v0: <span>
v0 = sqrt (d * g/ sin(2 θ)) </span>

<span>v0 = 10.383 m/s</span>

8 0
3 years ago
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