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asambeis [7]
3 years ago
6

The acceleration due to gravity jupiter is 25m/s Square . what does it mean​

Physics
2 answers:
vfiekz [6]3 years ago
8 0

Answer:

Explanation:

If any object is dropped from a height above the Jupiter's surface the object will fall towards jupiter's surface with a constant acceleration of 25m/s^2.

lions [1.4K]3 years ago
4 0

Answer:

The acceleration due to gravity of Jupiter is 25 m/s^2. means that, Any object dropped near Jupiter's Surface will accelerate downward (towards the Jupiter's surface) at the rate of 25 m/s^2 due to the gravity of Jupiter

Explanation:

hope it's help

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In normal light conditions, how well do plants grow when there are 10 plants in the
Sati [7]

Answer

when there are ten they don't grow so well but when there is less than 10 they tend to grow

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Which of the following is equal to Velocity change per second​
Mademuasel [1]

Acceleration

Explanation:

Acceleration is a physical quantity that expresses the change in the velocity of a body per unit of time.

  Acceleration = \frac{V - U }{T}

V is the initial velocity

U is the final velocity

T is the time

It is has a unit of m/s²

Learn more:

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#learnwithBrainly

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3 years ago
Mountains are part of which earth sphere?? Am I correct?
sammy [17]
You are correct. Mountains are part of the lithosphere.
8 0
3 years ago
Read 2 more answers
A ball was positioned in the middle of a smooth ramp and allowed to roll
netineya [11]

Answer:

it is quicker

Explanation:

6 0
2 years ago
The pressure P (in kilopascals), volume V (in liters), and temperature T (in kelvins) of a mole of an ideal gas are related by t
stich3 [128]

Answer:

\dfrac{dV}{dt} = -0.466 m^3/s

Explanation:

given,

P (in kilo pascals),         volume V (in liters),        temperature T (in kelvins)

P V = 8.31 T

Rate of increase the temperature =  0.1 K/s

temperature = 285 K

Pressure = 18 kPa

increasing at the rate of 0.07 k Pa/s

Rate at which volume is changing = ?

V = 8.31 \dfrac{T}{P}

\dfrac{dV}{dt} = 8.31 \dfrac{P\dfrac{dT}{dt}-T\dfrac{dP}{dt}}{P^2}

\dfrac{dV}{dt} = 8.31 \dfrac{18 \times 0.1-285\times 0.07}{18^2}

\dfrac{dV}{dt} = 8.31 \dfrac{-18.15}{324}

\dfrac{dV}{dt} = -0.466 m^3/s

7 0
3 years ago
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